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krok68 [10]
3 years ago
10

Problem: Write the Python code of a program called ComputeSquare that asks the user to enter the length of the side of the squar

e and displays the area and perimeter of the square. Check that the side length is greater than zero, and if it is not, display an informative error message to the user. ​
Computers and Technology
1 answer:
Lera25 [3.4K]3 years ago
6 0
<h2>Solution :</h2>

The given problem is solved in Python.

def ComputeSquare():

side = float(input('Enter the side of the square: '))

if side > 0:

perimeter = 4 * side

area = side * side

print('Perimeter of the square is:',

perimeter, 'unit.')

print('Area of the square is:', area, 'square unit.')

<h3> else:</h3>

print('Invalid input.')

ComputeSquare()

<h2>Explanation :-</h2>

  • In this program, we create a function ComputeSquare() to calculate the perimeter and area of a square.

  • The function asks the user to enter the side of the square. The side is then stored in a variable.

  • Now, we check whether the side is greater than 0 or not using if-else statement.

  • If the condition is true, the perimeter and area is calculated which is displayed using print() statement.

  • If the condition is false, the else blocks executes printing the error message.

<h3>Refer to the attachment for output.</h3>

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Answer:

7

Explanation:

#include <stdio.h>

int max2(int x, int y) {

   int result = y;

   if (x > y) {

       result = x;

   }

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   printf("%d",max3(a, b, c));

   printf("");

   return 0;

}

Hi, first of all, next time you post the question, it would be nice to copy and paste like above. This will help us to read the code easily. Thanks for your cooperation.

We start from the main function:

The variables are initialized → a = 5, b = 7, c = 3

max3 function is called with previous variables and the result is printed → printf("%d",max3(a, b, c));

We go to the max3 function:

It takes 3 integers as parameters and returns the result of → max2(max2(x,y),z)

Note that max2 function is called two times here (One call is in another call actually. That is why we need to first evaluate the inner one and use the result of that as first parameter for the outer call)

We go to the max2 function:

It takes 2 integers as parameters. If the first one is greater than the second one, it returns first one. Otherwise, it returns the second one.

First we deal with the inner call. max2(x,y) is max2(5,7) and the it returns 7.

Now, we need to take care the outer call max2(7, z) is max2(7, 3) and it returns 7 again.

Thus, the program prints 7.

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See full question below

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