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3 years ago

What is the answer to 6.4n-10=4.4n+6

Mathematics

2 answers:

bezimeni [28]3 years ago

4 0

6.4n - 10 = 4.4n + 6

Add 10 to both sides

6.4n = 4.4n + 16

Subtract 4.4n from both sides

2n = 16

Divide both sides by 2

n = 8

ycow [4]3 years ago

3 0

Answer:

Step-by-step explanation:

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HELPPPPPPPP<br><br> In WXY, y=690 cm, w=440 cm and angle X=163°. Find angle W to the nearest degree

Ede4ka [16]

Answer:

The angle W is approximately 7°.

Step-by-step explanation:

Since angle X is adjacent to sides y and w and opposite to side x, we calculate the length of side x by Law of the Cosine:

$x = \sqrt{y^2+w^2-2\cdot y\cdot w \cdot \cos X}$ (1)

Where:

$y, z$ - Side lengths, in centimeters.

$W$ - Angle, in sexagesimal degrees.

If we know that $y = 690\,cm$ , $w = 440\,cm$ and $X = 163^{\circ}$ , then the length of the side x is:

$x = \sqrt{y^2+w^2-2\cdot y\cdot w \cdot \cos X}$

$x\approx 1118.199\,cm$

By Geometry we know that sum of internal angles in a triangle equals 180°. If X is an obtuse, then Y and W are both acute angles. By Law of the Sine we find angle W:

$\frac{x}{\sin X}= \frac{w}{\sin W}$ (2)

$\sin W = \left(\frac{w}{x} \right)\cdot \sin X$

$W = \sin^{-1}\left[\left(\frac{w}{x} \right)\cdot \sin X\right]$

If we know that $X = 163^{\circ}$ , $w = 440\,cm$ and $x\approx 1118.199\,cm$ , then the angle W is:

$W = \sin^{-1}\left[\left(\frac{w}{x} \right)\cdot \sin X\right]$

$W \approx 6.606^{\circ}$

Hence, the angle W is approximately 7°.

3 0

3 years ago

I need help now. wich two

Kruka [31]

B and D is the answer

5 0

4 years ago

An object is experiencing an acceleration of 30 m/s2 while traveling in a

mixas84 [53]

Answer:

${ \tt{formular :}} \\ { \boxed{ \bf{centripental \: acceleration = \frac{ {v}^{2} }{r} }}} \\ \\ { \tt{30= \frac{ {3.7}^{2} }{r} }} \\ \\ { \tt{r = \frac{ {3.7}^{2} }{30} }} \\ \\ { \tt{radius = 0.456 \: meters}}$