Part A: In (0,4) and (1,8), as x increases from 0 to 1, y increases from 4 to 8. The slope of the line connecting these 2 pts. is (8-4) / (1-0), or 4. Now do the same thing for the 2 pts (1,8) and (2, 10). You will find that the slope in the 2nd case is different. Thus, the 3 given pts do NOT lie on a straight line. Function is non-linear.
Part B: an example of a non-linear function would be y = 2x^2 - 5. You can tell immediately from that exponent, 2, that this function is non linear.
An ex. of a linear function would include x to the 1st power only: y = 3x - 7.
Answer:
B. Good
Step-by-step explanation:
26-35 age group:
Excellent - 33/97
Good - 50/97
Average - 5/97
Poor - 9/97
14x-2/-2=0
14x-2=0*-2
14x-2=0
14x=2
14/2=x
x=7
Hope this helps :)!
To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
Circumference of a circle = 2πr
Circumference of the whole circle= 2π(30) = 60π
360 - 90 = 270
Length XPY = 270/360 x 60π = 45π
Answer: 45π m
