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2 years ago

14

Can anyone answer these questions?

1 answer:

sdas [7]2 years ago

6 0

Answer:

g^2=49

7^2=49

g=7

hope it is helpful to you

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In a standard deck of cards there 52 cards of which 26 are black and 26 are red. Additionally, there are 4 suits, hearts, clubs,

stich3 [128]

Using probability concepts, it is found that P(S and D) = 0.1275.

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A probability is the <u>number of desired outcomes divided by the number of desired outcomes</u>.
In a standard deck, there are 52 cards.
Of those, 13 are spades, and 13 are diamond.

The probability of selecting a spade with the first card is 13/52. Then, there is a 13/51 probability of selecting a diamond with the second. The same is valid for diamond then space, which means that the probability is multiplied by 2. Thus, the desired probability is:

$P(S \cap D) = 2 \times \frac{13}{52} \times \frac{13}{51} = \frac{2\times 13 \times 13}{52 \times 51} = 0.1275$

Thus, P(S and D) = 0.1275.

A similar problem is given at brainly.com/question/12873219

7 0

1 year ago

If your cell phone bill was 67 Point $82 and there is a 7.5% late fee how much will your bill be with the late fee included

Ivenika [448]

$\frac{7.5}{100} = \frac{x}{82} \\ x = \frac{82 \times 7.5}{100} = \frac{615}{100 } = 6.15$
$82 + 6.15 = 88.15$
the answer is $88.15

7 0

2 years ago

Please help I need this for my homework

Anton [14]

The answer is b.
${a}^{2} + {b}^{2} = {c}^{2}$

5 0

2 years ago

Find the equation of the exponential function that passes through the points (- 1, 1/6) and (1, 2/3) and Use the form y = c * a

icang [17]

Answer:

y = 1/3*2^x

Step-by-step explanation:

<u>Given function</u>

y = c*a^x

The points (-1, 1/6) and (1, 2/3) lie on the graph

<u>Substitute the values of x and y to get the system of equations:</u>

1/6 = c*a^(-1) ⇒ 1/6 = c/a ⇒ a = 6c
2/3 = c*a^1 ⇒ 2/3 = ac

<u>Substitute a and solve for c:</u>

2/3 = 6c*c
1/9 = c²
c = √1/9
c = 1/3

<u>Find a:</u>

a = 6c = 6*1/3 = 2

<u>The equation of the function:</u>

y = 1/3*2^x

8 0

2 years ago

Try this hard Math Problem if you dare!!

Dennis_Churaev [7]

Answer:

a. $(x - 3)^2 + 16$

b. $8(x -7)^2$

c. $(a^2 - 1)(7x - 6)$ or $(a+1)(a-1)(7x-6)$

d. $(x^2-4)(x^2+3)$ or $(x-2)(x+2)(x^2+3)$

e. $(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

Step-by-step explanation:

$a.\ (x + 1)^2 - 8(x - 1) + 16$

Expand

$(x + 1)(x + 1) - 8(x - 1) + 16$

Open brackets

$x^2 + x + x + 1 - 8x + 8 + 16$

$x^2 + 2x + 1 - 8x + 24$

Collect Like Terms

$x^2 + 2x - 8x+ 1 + 24$

$x^2 - 6x+ 25$

Express 25 as 9 + 16

$x^2 - 6x+ 9 + 16$

Factorize:

$x^2 - 3x - 3x + 9 + 16$

$x(x -3)-3(x - 3) + 16$

$(x - 3)(x - 3) + 16$

$(x - 3)^2 + 16$

$b.\ 8(x - 3)^2 - 64(x-3) + 128$

Expand

$8(x - 3)(x - 3) - 64(x-3) + 128$

$8(x^2 - 6x+ 9) - 64(x-3) + 128$

Open Brackets

$8x^2 - 48x+ 72 - 64x+192 + 128$

Collect Like Terms

$8x^2 - 48x - 64x+192 + 128+ 72$

$8x^2 -112x+392$

Factorize

$8(x^2 -14x+49)$

Expand the expression in bracket

$8(x^2 -7x-7x+49)$

Factorize:

$8(x(x -7)-7(x-7))$

$8((x -7)(x-7))$

$8(x -7)^2$

$c.\ 7a^2x - 6a^2 - 7x + 6$

Factorize

$a^2(7x - 6) -1( 7x - 6)$

$(a^2 - 1)(7x - 6)$

The answer can be in this form of further expanded as follows:

$(a^2 - 1^2)(7x - 6)$

Apply difference of two squares

$(a+1)(a-1)(7x-6)$

$d.\ x^4 - x^2 - 12$

Express $x^4$ as $x^2$

$(x^2)^2 - x^2 - 12$

Expand

$(x^2)^2 +3x^2- 4x^2 - 12$

$x^2(x^2+3) -4(x^2+3)$

$(x^2-4)(x^2+3)$

The answer can be in this form of further expanded as follows:

$(x^2-2^2)(x^2+3)$

Apply difference of two squares

$(x-2)(x+2)(x^2+3)$

$e.\ a^{4n} -b^{4n}$

Represent as squares

$(a^{2n})^2 -(b^{2n})^2$

Apply difference of two squares

$(a^{2n} -b^{2n})(a^{2n} +b^{2n})$

Represent as squares

$((a^{n})^2 -(b^{n})^2)(a^{2n} +b^{2n})$

Apply difference of two squares

$(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

6 0

2 years ago