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2 years ago

Find the value of a I’m decided go between 40 and 6.4

Mathematics

2 answers:

abruzzese [7]2 years ago

4 0

10 is the answer.
What you decided?

8_murik_8 [283]2 years ago

4 0

A = 10
Since the triangles are similar, you can set up a proportion using the corresponding sides and solve.
(16/8 = 20/a)
Hope this helps!

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Simplify the ratio 24:81

gizmo_the_mogwai [7]

Answer:

8 to 27

Step-by-step explanation:

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2 years ago

Write the equation of the circle that has a center of (-7, 17) with<br> a radius of V19.

kipiarov [429]

I think your question seems to be :-

Write the equation of the circle that has a center of (-7, 17) with a radius of √19

So , as we know that the equation of circle with centre at <em>(h,k)</em> and <em>radius r</em> is given by ${\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}}$ . Now , using same concept in this question ;

${:\implies \quad \sf \{x-(-7)\}^{2}+(y-17)^{2}=(\sqrt{19})^{2}}$

${:\implies \quad \bf \therefore \quad \underline{\underline{(x+7)^{2}+(y-17)^{2}=19}}}$

<em>This is the required equation of Circle </em>

8 0

1 year ago

Solve for x 5 – 57− 2 = 63 please help

umka2103 [35]

5x - 2x = 63 + 57
3x = 120
x = 40

4 0

2 years ago

Solve the formula t=v+k/g for g

Brut [27]

$t=v+\frac{k}{g}\\\\v+\frac{k}{g}=t\ \ \ \ |subtract\ v\ from\ both\ sides\\\\\frac{k}{g}=t-v\iff\frac{g}{k}=\frac{1}{t-v}\ \ \ \ |multiply\ both\ sides\ by\ k\neq0\\\\\boxed{g=\frac{k}{t-v}}$

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3 years ago

The quadratic function g(x) = a.ca + bx+c has the

Mumz [18]

<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

$f(x)=ax^2+bx+c$

Here we know that the leading coefficient $a=1$ so we reduce our equation to:

$g(x)=x^2+bx+c$

The roots are those values at which $g(x)=0$

So:

$x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\ 49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\$

$Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\ 49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0$

So we have:

$(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}$

Finding c from (1):

$33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}$

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

5 0

2 years ago