Question

Four cups of a salad blend containing 40% spinach is mixed with an unknown amount of a salad blend containing 55% spinach. the resulting salad contains 50% spinach.how many cups of salad are in the resulting mixture?

Answer 1

Four cups of a salad blend containing 40% spinach is mixed with an unknown amount of a salad blend containing 55% spinach. the resulting salad contains 50% spinach.

Let x the amount 55% salad blend

Y = the amount of 50%

The equation:

4 + x = y

4(0.40) +0.55x = 0.50y

Solving the equation

X = 8 cups

Y = 12 cups of the resulting mixture

Answer 2

Answer:

12 cups of salad are in the resulting mixture.

Step-by-step explanation:

Four cups of a salad blend have 40% spinach,

So the amount of spinach is,

$=4\times \dfrac{40}{100}$

Let x amount of salad blend is mixed with 55% spinach.

So the amount of spinach is,

$=x\times \dfrac{55}{100}$

As both the cups were mixed, so the net amount will be (4+x) cups.

The result has 50% spinach, so the amount of spinach is,

$=(4+x)\times \dfrac{50}{100}$

As the amount of spinach is same, so

$\Rightarrow (4+x)\times \dfrac{50}{100}=4\times \dfrac{40}{100}+x\times \dfrac{55}{100}$

$\Rightarrow \dfrac{50(4+x)}{100}=\dfrac{160+55x}{100}$

$\Rightarrow 50(4+x)=160+55x$

$\Rightarrow 200+50x=160+55x$

$\Rightarrow 55x-50x=200-160$

$\Rightarrow 50x=40$

$\Rightarrow x=8$

So, total amounts of mixture will be 4+8=12 cups.