Which expression can be used to find the difference of the polynomials?

Consider the transformation shown. 2 triangles are shown. The first is labeled pre-image and the second is labeled image. Both t

dlinn [17]

The transformation is non-rigid because the side lengths are not preserved.

<h3>How to complete the drop-down menus?</h3>

The drop-down menus and the image of the triangles are not given.

However, the question can still be solved using the available parameters.

The given parameters are:

Pre-image: 6, 10, 8

Image: 3, 5, 8

See that the side lengths of the image and the pre-image are not the same

This means that the transformation is a non-rigid transformation

Hence, the complete statement is the transformation is non-rigid because the side lengths are not preserved.

Read more about transformation at:

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3 0

3 years ago

A coin is flipped eight times where each flip comes up either heads or tails. How many possible outcomes a) are there in total?

attashe74 [19]

Answer:

There are 256 ways in total.

There are 56 possible outcomes contain exactly three heads.

The possible outcomes contain at least three heads is 219.

The possible outcomes contain the same number of heads and tails are 70.

Step-by-step explanation:

Consider the provided information.

A coin is flipped eight times where each flip comes up either heads or tails.

Part (a) How many possible outcomes are there in total?

Each time we flip a coin it comes up either heads or tail.

Therefore the total number of ways are:

$2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^8=256$

Hence, there are 256 ways in total.

Part (b) contain exactly three heads?

We want exactly 3 heads, therefore,

n=8 and r=3

According to the definition of combination: $\binom{n}{r}=\frac{n!}{r!(n-r)!}$

$\binom{8}{3}=\frac{8!}{3!(5)!}=56$

Hence, there are 56 possible outcomes contain exactly three heads.

Part (c) contain at least three heads?

For 3 heads: $\binom{8}{3}=\frac{8!}{3!(5)!}=56$

For 4 heads: $\binom{8}{4}=\frac{8!}{4!(4)!}=70$

For 5 heads: $\binom{8}{5}=\frac{8!}{5!(3)!}=56$

For 6 heads: $\binom{8}{6}=\frac{8!}{6!(2)!}=28$

For 7 heads: $\binom{8}{7}=\frac{8!}{7!(1)!}=8$

For 8 heads: $\binom{8}{8}=1$

Now add them as shown:

56+70+56+28+8+1=219

Hence, the possible outcomes contain at least three heads is 219.

Part (d) contain the same number of heads and tails?

Same number of heads and tails means that the value of r=4.

Therefore,

$\binom{8}{4}=\frac{8!}{4!(4)!}=70$

Hence, the possible outcomes contain the same number of heads and tails are 70.

6 0

3 years ago

Find the length of the function over the given interval. y = 3x from x = 0 to x = 2

olganol [36]

The length of the function y = 3x over the given interval [0, 2] is 3.2 units

For given question,

We have been given a function y = 3x

We need to find the length of the function on the interval x = 0 to x = 2.

Let f(x) = 3x where f(x) = y

We have f'(x) = 3, so [f'(x)]² = 9.

Then the arc length is given by,

$\int\limits^a_b {\sqrt{1+[f'(x)]^2} } \, dx\\\\= \int\limits^2_0 {\sqrt{1+9} }\, dx\\\\=\sqrt{10}\\\\ =3.2$

This means, the arc length is 3.2 units.

Therefore, the length of the function y = 3x over the given interval [0, 2] is 3.2 units

Learn more about the arc length here:

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3 0

2 years ago

3<br>If x=<br>)<br>X Х<br>find the value of x-2<br>3<br>2.

Slav-nsk [51]

Step-by-step explanation:

Answer

Open in answr app

Correct option is

B

±2

x=3+22 x1=3+221×3−223−22

=3−22

(x−21)2=x+x1−2

=3+22+3−22−2=4

So, x−x1=4=±2 Ans

6 0

3 years ago

A dentist orders 15 boxes of floss and 20 boxes of toothbrushes each month floss is sold 70 to a box and toothbrushes are sold 5

tatiyna

Answer:

1050 toothbrushes and 1000 floss.

Step-by-step explanation:

15x70=1050

20x50=1000

Hope it helps!

8 0

4 years ago