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2 years ago

What are 5 applications of Geometry in real life?

Mathematics

1 answer:

Xelga [282]2 years ago

4 0

Answer:

•construction of buildings

•Interior designs

•Art

•Measuring of orbits and planetary •motions Interior designs

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Alex had $750,000 he lost 80% how many dollars did he lose

Stels [109]

Answer:

$600,000

Step-by-step explanation:

GIven;

Alex had $750,000 he lost 80%

To Find;

How many dollars did he lose

Solve;

$750,000 * 80% = 600,000

Hence, Alex lost $600,000.

~Learn with Lenvy~

8 0

1 year ago

Read 2 more answers

-5(-7,3) in y=mx+b form

kenny6666 [7]

Assuming -5 is m

y-3 = -5 (x + 7)
y - 3 = -5x - 35
y = -5x - 33

hope this helps , give brainliest.

7 0

3 years ago

Match each function with its function. Use function composition to determine your answer

Ket [755]

Answer:

Step-by-step explanation:

idk

8 0

2 years ago

As Sally and George practice for the SAT their scores on practice test rise Sally’s current score is 850 and it is rising by 10

aleksley [76]

Answer:

a) 7 weeks b) George's

Step-by-step explanation:

Sally's score can be modeled by 10x+850.

George's score can be modeled by 50x+570.

We can set them equal to each other to see when they intersect.

10x+850=50x+570

40x=280

x=7

If George overtakes her in the 7th week, of course he'll have the higher score in 12 weeks.

3 0

2 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

Answer:

3003 number of 5-member chess teams can be chosen from 15 interested players.

Step-by-step explanation:

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{360360}{120}$

$15C_5 = 3003$

7 0

2 years ago