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3 years ago

I need help in algebra

Mathematics

2 answers:

Wittaler [7]3 years ago

6 0

Answer: 8

Step-by-step explanation:

Anna007 [38]3 years ago

3 0

Answer:

Step-by-step explanation:

How to solve

× + 5 = 13

subtract from both sides of the equation.

× + 5 - 5 = 13 - 5

13 - 5= 8

please give me brainliest and a thanks.

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Find the sum of 6+(-6).

balandron [24]

Answer:

Step-by-step explanation:

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4 years ago

If a quadrilateral is a square, then it is also a rectangle. True or False

marshall27 [118]

Answer:

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3 years ago

-7.2x+3.5=-8.7x-10 help plz

m_a_m_a [10]

-7.2x + 8.7x = -3.5 - 10
1.5x = -13.5
x = -13.5/1.5
x = -9

5 0

3 years ago

Can someone help me with these 5 question I have attached?

Contact [7]

Example 2: x=10

Example 3: x=-1

Example 4: x=35

Example 5: a-b+c=9

Example 6: x=1, x=1/2

Further explanation:

Example 2:

$\sqrt{4x-4} =6$

Taking Square on both sides

$(\sqrt{4x-4})^2 =(6)^2\\4x-4=36\\4x=36+4\\4x=40\\\frac{4x}{4}=\frac{40}{4}\\x=10$

Example 3:

$9+\sqrt{4x+8}=11$

Subtracting 9 from both sides

$9-9+\sqrt{4x+8}=11-9\\\sqrt{4x+8}=2\\$

Taking Square on both sides

$(\sqrt{4x+8})^2=(2)^2\\4x+8=4\\4x=4-8\\4x=-4\\\frac{4x}{4}=-\frac{4}{4}\\x=-1$

Example 4:

$8+\sqrt{x+1}=2$

subtracting 8 from both sides

$8-8+\sqrt{x+1}=2-8\\\sqrt{x+1}=-6$

Taking Square on both sides

$(\sqrt{x+1})^2=(-6)^2\\x+1=36\\$

Subtracting 1 from both sides

$x+1-1=36-1\\x=35$

Example 5:

$\sqrt{a-b+c}=3$

Taking Square on both sides

$(\sqrt{a-b+c})^2=(3)^2\\a-b+c=9\\$

Example 6:

$2\sqrt{2x-1}=4x-2$

Taking square on both sides

$(2\sqrt{2x-1})^2=(4x-2)^2\\4(2x-1)=16x^2+4-16x\\8x-4=16x^2-16x+4\\8x=16x^2-16x+4+4\\8x=16x^2-16x+8\\16x^2-16x-8x+8=0\\16x^2-24x+8=0$

dividng whole equation by 8

$2x^2-3x+1=0\\2x^2-2x-x+1=\\2x(x-1)-1(x-1)=0\\(2x-1)(x-1)=0\\2x-1=0 => x=\frac{1}{2}\\x-1=0 => x=1$

Keywords: Radical Expressions, Examples

Learn more about radical expressions at:

#LearnwithBrainly

3 0

3 years ago

Alexis has $3.25 in nickels and dimes. The number of dimes is 5 less than twice the number of nickels. Find the number of nickel

jek_recluse [69]

Answer:

15 nickels were there with Alexis

Step-by-step explanation:

Let there be x nickels

given that

The number of dimes is 5 less than twice the number of nickels.

no of dimes in terms of x = 2*number of nickels - 5 = 2x - 5

we know that

value of 1 nickel = 5 cents

then

value of x nickel = 5*x cents = 5x cents

we know that

value of 1 dime = 10 cents

then

value of 2x-5 dime = 10(2x - 5) cents = 20x - 50 cents

Total value of x nickel and 2x -5 dimes = 5x + 20x - 50 = 25x - 50

given that

Alexia has total of $3.25 in nickel and dimes thus 25x - 50 must be equal to $3.25

$1 = 100 cents

$3.25 = 3.25 * 100 cents = 325 cents

Thus,

25x - 50 = 325

25x = 325 + 50 = 375

x = 375/25 = 15

Thus, no of nickels = x = 15 answer

5 0

3 years ago