Answer:
$2355.06
Step-by-step explanation:
Use the compound interest formula, filling in the numbers you know. Then solve for the number you don't know.
A = P(1 +r/n)^(nt)
where A is the account balance, P is the amount invested, r is the annual rate, n is the number of times per year interest is compounded, and t is the number of years.
Filling in the given values, we have ...
4000 = P(1 +.053/52)^(52·10) = P(1.6984738)
P = 4000/1.6984738 ≈ 2355.06
You would need to deposit $2355.06 in order to have $4000 in 10 years.
Answer: Approximately 95% of the students spent between $<u> 420</u> and $<u> 544</u> on textbooks in a semester.
Step-by-step explanation:
When data is normally distributed,
Then , according to the Empirical rule , approximately 95% of the data lies with in the 2 standard deviations from mean.
Given : The distribution of the amount of money spent by students on textbooks in a semester is approximately normal in shape with
Mean = 482 standard deviation = 31.
Then , by
Empirical rule , approximately 95% of the students spent between Mean ± 2 (Standard deviation) on textbooks in a semester.
where , Mean ± 2 (Standard deviation) = 482 ± 2(31)
=(482-2(31) , 482+2(31))
=(420 , 544)
Hence , Approximately 95% of the students spent between $<u> 420</u> and $<u> 544</u> on textbooks in a semester.
3 * 4.5 is how to solve it I think for the