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Mars2501 [29]
3 years ago
12

5/-7x (-9y/8) multiply and simplify ​

Mathematics
1 answer:
LekaFEV [45]3 years ago
7 0

Answer:

\large\boxed{\dfrac{5}{-7x}\cdot\dfrac{-9y}{8}=\dfrac{45y}{56x}}

Step-by-step explanation:

\dfrac{5}{-7x}\cdot\dfrac{-9y}{8}=\dfrac{(5)(-9y)}{(-7x)(8)}=\dfrac{-45y}{-56x}=\dfrac{45y}{56x}

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To offset college expenses, at the beginning of your freshman year you obtain a nonsubsidized student loan for $15,000. Interest
soldier1979 [14.2K]

Answer:

15000(1.003425)^12t ;

4.11%

4.188%

Step-by-step explanation:

Given that:

Loan amount = principal = $15000

Interest rate, r = 4.11% = 0.0411

n = number of times compounded per period, monthly = 12 (number of months in a year)

Total amount, F owed, after t years in college ;

F(t) = P(1 + r/n)^nt

F(t) = 15000(1 + 0.0411/12)^12t

F(t) = 15000(1.003425)^12t

2.) The annual percentage rate is the interest rate without compounding = 4.11%

3.)

The APY

APY = (1 + APR/n)^n - 1

APY = (1 + 0.0411/12)^12 - 1

APY = (1.003425)^12 - 1

APY = 1.04188 - 1

APY = 0.04188

APY = 0.04188 * 100% = 4.188%

7 0
3 years ago
HELPPP!!! I NEED HELP WITH 1-6!!!
xeze [42]

Explanation: turn the percentage into a decimal, like for number 4 make it 0.40
then divide it by 30
Really hopes this helps!
5 0
3 years ago
What do you do to both sides to<br> r? What is r? 3/8 r = 6 HELP ME
faust18 [17]

Answer:

r = 16

Step-by-step explanation:

\frac{3}{8}r = 6 \\\\

Multiply both sides by 8

8*\frac{3}{8}r = 6*8\\\\3r = 48\\

Divide both side by 3

\frac{3}{3}r=\frac{48}{3}\\\\r = 16

OR

Multiply both side by (8/3)

\frac{8}{3}*\frac{3}{8}r=6*\frac{8}{3}\\\\r = 2*8\\\\r = 16

write an equation to represent the information in this problem. Jerel runs five days each week. on each of 4 days, he runs 2.3 km. if jerel runs a total of 14km, how many kilometers does he run on the fifth day?

Let x be the distance run on the fifth day

Total distance run on all the four days = 2.3 * 4 = 9.2 km

Required equation : x + 9.2 = 14

x = 14 - 9.2

x = 4.8 km

3 0
2 years ago
Find a vector of magnitude 3 in the direction of v = 10i - 24k. The vector is Oi-Oj+k (Simplify your answer. Use integers or fra
Soloha48 [4]

Given :

A vector v = 10i - 24k.

To Find :

A vector of magnitude 3 in the direction of v = 10i - 24k.

Solution :

Unit vector in the direction  of vector v is :

\^{v}=\dfrac{v}{|v|}\\\\\^{v}=\dfrac{10i-24k}{\sqrt{10^2+24^2}}\\\\\^{v}=\dfrac{10i-24k}{26}

Now , vector of magnitude 3 in direction v is :

r=3 \^{v}\\\\r=3\times \dfrac{ (10i-24k)}{26}\\\\r=\dfrac{3}{13} (5i-12k)

Hence , this is the required solution .

6 0
3 years ago
What is the result of 3-5?<br> 0<br> 2<br> 2<br> 3<br> 1<br> 9<br> 1<br> 5<br> 9
cestrela7 [59]

Answer:

4-7

Step-by-step explanation:

5 0
3 years ago
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