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dimaraw [331]
3 years ago
8

Simple geometry can compute the height of an object from the the object's shadow length and shadow angle using the formula: tan(

angleElevation) = treeHeight / shadowLength. Given the shadow length and angle of elevation, compute the tree height.Sample program:#include #include int main(void) { double treeHeight = 0.0; double shadowLength = 0.0; double angleElevation = 0.0; angleElevation = 0.11693706; // 0.11693706 radians = 6.7 degrees shadowLength = 17.5; printf("Tree height: %lf\n", treeHeight); return 0;}
Computers and Technology
1 answer:
agasfer [191]3 years ago
7 0

Answer:

The program to this question can be given as:

Program:

#include <stdio.h>  //include header files

#include<math.h>

int main()    //main method  

{        

   double treeHeight = 0.0;         //declare variables

and assign value

   double shadowLength = 0.0;  

   double angleElevation =  0.11693706;

   // (0.11693706 radians = 6.7 degrees) convert number into angle.      

   shadowLength = 17.5;  

treeHeight = shadowLength * tan(angleElevation);   //convert number into angle

   printf("Tree height: %lf\n", treeHeight);   //print value.

   return 0;  

}

Output:

Tree height: 2.055778

Explanation:

In the above C language program firstly we include the headers. In this header file, we include a (math.h) header file this file helps to use the math function. Then we declare the main method in the main method we declare the variable that is given in the question that are treeHeight, shadowLength , angleElevation. All the variable datatype is double because it stores the floating-point value. Then we apply the formula that is  treeHeight = shadowLength * tan(angleElevation). In this formula, the treeHeight variable holds the value. Then we print the variable value for print the double value we use the lf(that is long float).

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Of translating an idea or a thought into a code

Explanation:

Encoding is the process of translating an idea or a thought into a code.

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Use semaphore(s) to solve the following problem. There are three processes: P1, P2, and P3. Each process Pi has a segment of cod
Lisa [10]

Answer:

See explaination

Explanation:

Here we will use two semaphore variables to satisfy our goal

We will initialize s1=1 and s2=1 globally and they are accessed by all 3 processes and use up and down operations in following way

Code:-

s1,s2=1

P1 P2 P3

P(s1)

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Explanation:-

The P(s1) stands for down operation for semaphore s1 and V(s1) stands for Up operation for semaphore s1.

The Down operation on s1=1 will make it s1=0 and our process will execute ,and down on s1=0 will block the process

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Now in the above code:

1)If C1 is executed first then it means down on s1,s2 will make it zero and up on s2 will make it 1, so in that case C3 cannot execute because P3 has down operation on s1 before C3 ,so C2 will execute by performing down on s2 and after that Up on s1 will be done by P2 and then C3 can execute

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2)If C1 is not executed earlier means:-

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b)If C3 is executed by performing down on s1 then s1=0 ,so definitely C2 will be executed now ,because down on s1 will block the process P1 and after that P2 will perform up on s1 ,so P1 gets unblocked

So C1 will be executed after C2 and C3 ,hence our 2nd condition satisfied.

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True

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