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3 years ago

The histogram presents the compressive strengths of a sample of concrete blocks hardened for 28 days.

Mathematics

1 answer:

dusya [7]3 years ago

3 0

Answer:

The question is not complete but I have uploaded the image to complete the question.

The missing rectangle has a relative frequency of 0.15, and this is the same as the height.

Step-by-step explanation:

Let us define what a frequency and relative frequency are

The frequency of a datum is the number of times a given item (datum) appears in the data set.

While the relative frequency is the fraction or proportion of times taken from the whole in which an item/datum occurs.

So, from the image I uploaded, the relative frequency column represents the height of the histogram. Let the height of the missing rectangle be x.

Therefore the heights of the rectangles written from left to right are 0.05, 0.1, 0.15, x, 0.25, 0.2, and 0.1.

From the definition of relative frequency, the total sum of relative frequency is 1, if represented as decimals or fractions it can either be expressed in percentage, or decimal (fractions). In this question, it is represented in decimal, and the sum of all the relative frequency is 1.

0.05 + 0.1 + 0.15 + x + 0.25 + 0.2 + 0.1 = 1 ;

0.85+ x =1

Therefore, x = 1 - 0.85= 0.15

You might be interested in

Find the factorial form 3x2x1

Lubov Fominskaja [6]

Answer:

3x2x1=3!

Step-by-step explanation:

using nx(n-1)x_x1=n

3x2x1=3!

hence,3x2x1=3!

8 0

3 years ago

Select the statements that are true based on the following given information. D = {x | x is a whole number} E = {x | x is a perf

likoan [24]

<h3>2 Answers: Choice C and Choice D</h3>

==========================================================

Explanation:

Let's write the roster notation of each set

D = {0, 1, 2, 3, ...} the dots indicate the pattern goes on forever

E = {0, 1, 4, 9, 16, 25} = list of perfect squares smaller than 36

F = {20, 22, 24, 26, 28, 30} = even numbers between 20 and 30

----------------

If we intersect sets D and E, we're looking for what numbers are in both sets at the same time. Therefore, D ∩ E = {0, 1, 4, 9, 16, 25} which is the exact same as set E. This is because all of set E is inside of set D. We say that set E is a subset of set D. So, D ∩ E = E.

Choice A is very close to being true. The problem is that 25 is missing from the set {1,4,9,16}. So this is why choice A is false.

----------------

Now let's intersect sets D and F. The numbers they have in common are {20, 22, 24, 26, 28, 30} which is exactly what set F is. So set F is a subset of set D. We can write D ∩ F = F in much the same way we can say D ∩ E = E.

D ∩ F = {12,14,16,18} is not true. A number like 12 is not between 20 and 30, so it cannot be in set F.

Choice B is false so we cross it off the list.

----------------

Choice C is true and here's why

D ∪ (E ∩ F) is the same as saying D ∪ G where G is the set of intersecting E and F together. In other words, G = E ∩ F

We don't really need to even worry about sets E, F or G. All that matters here is set D.

When we write D ∪ (E ∩ F) or D ∪ G, we're saying "a number is in set D, or it is in set G". If it is in D, then it's a whole number. Otherwise, it's in a subset of whole numbers.

Overall, D ∪ G and D ∪ (E ∩ F) form the entire set of whole numbers.

------------------

Choice D is true.

E and F have nothing in common

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

So intersecting them leads to the empty set. This is the set with nothing inside it, not even 0.

------------------

Choice F is false

These two sets below

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

union together to get

H = {0,1,4,9,16,20,22,24,25,26,28,30}

just toss all of the numbers together into one big set

Notice how each of these numbers are whole numbers, so they are part of set D. This means set H is also a subset of set D.

When we intersect sets D and H, we end up with set H. We do not simply end up with the set with 25 only inside it.

6 0

3 years ago

Pliz answer this question

irina1246 [14]

Cent is by the hundred so one percent is 1/100 so .6%=6/1000
which can be reduced to 3/500

7 0

3 years ago

Determine the center and radius of the following circle equation:

-BARSIC- [3]

Answer:

(6, 9 ) and r = 3

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² - 12x - 18y + 108 = 0

Rearrange the x- terms and the y- terms together and subtract 108 from both sides, that is

x² - 12x + y² - 18y = - 108

To obtain standard form use the method of completing the square

add ( half the coefficient of the x and y terms )² to both sides

x² + 2(- 6)x + 36 + y² + 2(- 9)y + 81 = - 108 + 36 + 81

(x - 6)² + (y - 9)² = 9 ← in standard form

with centre = (6, 9 ) and r = $\sqrt{9}$ = 3

7 0

3 years ago

SSA triangles always have two solutions. (A.) True (B). False

scoray [572]

Answer:

No, Ssa triangle always not have two solutions

Step-by-step explanation:

the solution can be one, two or there will be no dolution. So this statement is false.

8 0

2 years ago

Read 2 more answers