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Sergio039 [100]

3 years ago

9

1. Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into

a hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 10?

1 answer:

Ludmilka [50]3 years ago

5 0

Answer:

5, assuming you get the worst possible slips off: 0,1,2,3,4

Step-by-step explanation:

You might be interested in

uppose that Mary's utility function is U(W) = W0.5, where W is wealth. She has an initial wealth of $100. How much of a risk

Stels [109]

Note that $U(W) = W^{0.5}$

Answer:

Mary's risk premium is $0.9375

Step-by-step explanation:

Mary's utility function, $U(W) = W^{0.5}$

Mary's initial wealth = $100

The gamble has a 50% probability of raising her wealth to $115 and a 50% probability of lowering it to $77

Expected wealth of Mary, $E_w$

$E_{w}$ = (0.5 * $115) + (0.5 * $77)

$E_{w}$ = 57.5 + 38.5

$E_{w}$ = $96

The expected value of Mary's wealth is $96

Calculate the expected utility (EU) of Mary:-

$E_u = [0.5 * U(115)] + [0.5 * U(77)]\\E_u = [0.5 * 115^{0.5}] + [0.5 * 77^{0.5}]\\E_u = 5.36 + 4.39\\E_u = \$ 9.75$

The expected utility of Mary is $9.75

Mary will be willing to pay an amount P as risk premium to avoid taking the risk, where

U(EW - P) is equal to Mary's expected utility from the risky gamble.

U(EW - P) = EU

U(94 - P) = 9.63

Square root (94 - P) = 9.63

If Mary's risk premium is P, the expected utility will be given by the formula:

$E_{u} = U(E_{w} - P)\\E_{u} = U(96 - P)\\E_u = (96 - P)^{0.5}\\(E_u)^2 = 96 - P\\ 9.75^2 = 96 - P\\95.0625 = 96 - P\\P = 96 - 95.0625\\P = 0.9375$

Mary's risk premium is $0.9375

7 0

2 years ago

mamaluj [8]

The first one is the correct answer

Y-7=-3(x+2)

6 0

2 years ago

Place the three functions in order from the fastest decreasing average rate of change to the slowest decreasing average rate of

victus00 [196]

Answer:

g(x), f(x) and h(x)

Step-by-step explanation:

Given

Interval: (0,3)

See attachment for functions f(x), g(x) and h(x)

Required

Order from fastest to slowest decreasing average rate of change

The average rate of change is calculated as:

$Rate = \frac{f(b) - f(a)}{b - a}$

In this case:

$(a,b) = (0,3)$

i.e.

$a = 0\\b=3$

For f(x)

$f(x) = 16(\frac{1}{2})^x$

$Rate = \frac{f(b) - f(a)}{b - a}$

$Rate = \frac{f(3) - f(0)}{3 - 0}$

$Rate = \frac{f(3) - f(0)}{3}$

Calculate f(3) and f(0)

$f(x) = 16(\frac{1}{2})^x$

$f(3) = 16(\frac{1}{2})^3 = 16 * \frac{1}{8} = 2$

$f(0) = 16(\frac{1}{2})^0 = 16 * 1 = 16$

So:

$Rate = \frac{f(3) - f(0)}{3}$

$Rate = \frac{2 - 16}{3}$

$Rate = -\frac{14}{3}$

For g(x)

$Rate = \frac{g(b) - g(a)}{b - a}$

$Rate = \frac{g(3) - g(0)}{3 - 0}$

$Rate = \frac{g(3) - g(0)}{3}$

From the table of g(x)

$g(3) = 1$

$g(1) = 27$

So:

$Rate = \frac{1 - 27}{3}$

$Rate = -\frac{26}{3}$

For h(x)

$Rate = \frac{h(b) - h(a)}{b - a}$

$Rate = \frac{h(3) - h(0)}{3 - 0}$

$Rate = \frac{h(3) - h(0)}{3}$

From the graph of h(x)

$h(3) = -3$

$h(0) = 4$

So:

$Rate = \frac{-3 - 4}{3}$

$Rate = -\frac{7}{3}$

So, the calculated rates of change are:

$f(x) = -\frac{14}{3}$ $= -4.67$

$g(x) = -\frac{26}{3}$ $=-8.67$

$h(x) = -\frac{7}{3}$ $=-2.33$

By comparison:

From the fastest decreasing to slowest, the order is: <em>g(x), f(x) and h(x)</em>

4 0

2 years ago

Joe opened a book store. On the first three days he sold 15, 18, and 16 books (he initially hoped he sell 17 books everyday). Ho

soldi70 [24.7K]

$\frac{15 + 18 + 16 + x}{4} = 17 \\ \frac{49 + x}{4} = 17 \\ 49 + x = 17 \times4 \\ 49 + x = 68 \\ x = 68 - 49 \\ x = 19$
hope this helps! ask if you have anymore questions

5 0

2 years ago

Plsssssssss helppppppp

Maurinko [17]

the answer is the third one on the page that is it my dude

5 0

1 year ago