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3 years ago

What is the middle of a circle called

1 answer:

4 0

It would be called the center or center point. Think about it, "center" means to be in the middle. So the middle of the circle would be the center.
Hope this helps. :-)

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FREE POINTS! Also will mark Brainliest for the most detailed explanation.

Alexxandr [17]

Answer:

209,000

Step-by-step explanation:

(500+200=700)

(700*300=210000)

210000-1000=209,000

4 0

3 years ago

Read 2 more answers

Using elimination method

bogdanovich [222]

Answer:

The value of x is 2 and y is (-5)

Step-by-step explanation:

<h3>Given;</h3>

-7x + y = – 19
-2x + 3y = – 19

The value of x and y

<h3>By Using Elimination Method;</h3>

First name the equation

-7x + y = – 19 ...(1)
-2x + 3y = – 19 ...(2)

Now, Multiply equation (1) by 3 we get,

3 × (-7x + y = – 19)

-21x + 3y = – 57

Now, Eliminate

-21x + 3y = – 57

-2x + 3y = – 19

+ – +

-19x = -38

x = -38/-19

x = 2

Now, Put the value of x in equation (2) we get the value of y.

-7x + y = – 19

-7(2) + y = – 19

-14 + y = -19

-14 + 14 + y = -19 + 14

y = -5

Thus, The value of x is (-5) and the value of y is 2.

<h3>For Verification;</h3>

-7x + y = – 19

-7(2) + (-5) = – 19

-14 – 5 = – 19

-19 = -19

-2x + 3y = – 19

-2(2) + 3(-5) = – 19

-4 – 15 = – 19

-19 = -19

Here, L.H.S = R.H.S

Hence Verified!

-TheUnknownScientist 72

4 0

2 years ago

Help anyone please !!!

Serga [27]

Answer:

Itsb

Step-by-step explanation:

8 0

3 years ago

triangle FGH is an equilateral triangle with FG=x+5,GH=3x-9,and FH=2x-2 . find x and the measure of each side

Zigmanuir [339]

The sides of an equilateral triangle are equal length, so ...
GH = FH
3x-9 = 2x-2
x = 7 . . . . . . . . add 9-2x

Then the side lengths are
FG = x+5
FG = 7 +5 = 12

x = 7
FG = GH = FH = 12

6 0

3 years ago

Read 2 more answers

The data set below has a lower quartile of 13 and an upper quartile of 37.

Levart [38]

The dataset 78 is an outlier of the dataset

<h3>How to determine the true statement about the outlier?</h3>

The dataset is given as:

1, 12, 13, 15, 18, 20, 35, 37, 40, 78

Where

Q1 = 13

Q3 = 37

The boundaries of the outliers are given as:

L = Q1 - 1.5 * (Q3 - Q1)

U = Q3 + 1.5 * (Q3 - Q1)

Substitute the known values in the above equation

L = 13 - 1.5 * (37 - 13) = -23

U = 37 + 1.5 * (37 - 13) = 73

This means that the data elements outside the range -23 to 73 are outliers.

78 is outside this range

Hence, 78 is an outlier of the dataset