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dimaraw [331]
3 years ago
11

If I score 13 out of 24 in a test , what percentage is this ?

Mathematics
2 answers:
Vesnalui [34]3 years ago
8 0
13/24 would be 54% which is a D- (a fail)
Alina [70]3 years ago
4 0
The answer is 54% that is a fail.
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Estimate m :140 = m + 125
8090 [49]

The estimation for m would be 120. Happy thanksgiving

5 0
3 years ago
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En la escuela Francisco I. Madero de ciudad Delicias, llevaron a cabo el festejo para
REY [17]

Answer:

The number of unsold cakes was 2

Step-by-step explanation:

<u><em>The question in English is</em></u>

In the school Francisco I. Madero of Ciudad Delicias, the celebration was held for  commemorate the arrival of spring, after the parade the stalls were set up  of the kermesse. The first grade group bought 8 cakes and sold 3/4 of the total.

How much of the cake was not sold?

Let

x ----> number of cakes sold

y ----> number of cakes that didn't sell

we know that

The first grade group bought 8 cakes

so

x+y=8 -----> equation A

The first grade group sold 3/4 of the total.

so

x=\frac{3}{4}(x+y) ---> equation B

substitute equation A in equation B

x=\frac{3}{4}(8)=6

Find the value of y

6+y=8

y=2

therefore

The number of unsold cakes was 2

4 0
2 years ago
Please answer this correctly please label the numbers correctly
Ierofanga [76]

Answer:

Step-by-step explanation:

All u need to do is graph the points so for -4,5 go 4 left then go  up

8 0
3 years ago
Evaluate the expression for a = 5, b = 11, and c = 3. 2a + 2c(b − 5) A. 64 B. 46 C. 54 D. 163
Artemon [7]

2a +2c(b-5)

substitute a=5 b=11 c=3

2(5) +2(3) (11-5)

10+6(6)

10+36

46

Choice B


8 0
2 years ago
One bar of candy A and two bars of candy B have 774 calories. Two bars of candy A and one bar of candy B contains 786 calories.
vampirchik [111]
◆ Define the variables:

Let the calorie content of Candy A = a
and the calorie content of Candy B = b

◆ Form the equations:

One bar of candy A and two bars of candy B have 774 calories. Thus:

a + 2b = 774

Two bars of candy A and one bar of candy B contains 786 calories

2a + b = 786

◆ Solve the equations:

From first equation,
a + 2b = 774
=> a = 774 - 2b

Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie

◆ Find caloric content:

Caloric content of candy B = 254 calorie

Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
5 0
3 years ago
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