22.
pythagorean theorem says legs a and b and hypotenuse c of a right triangle are related via the equation c²=a²+b². in other words, adding the sum of the squares of the legs get you the square of the hypotenuse
if the hypotenuse is 4 meters long, c = 4.
if one leg is 3 meters long, we can choose either a or b to be 3. it does not really matter. let us choose a = 3. now we have to find b.
if we have c²=a²+b², we can solve for b.
subtract a² both sides to get c²-a²=b², and then square root both sides to get
b = √(c²-a²)
plugging in our info we get
b = √(4²-3²) = √(16 -9) = √7
so the answer is √7 meters for 22
23
two triangles are similar, then the proportion of their sides are the same. the propotion between the smaller triangles' hypotenuse and 2cm leg is 5cm/3cm.
notice how the bigger triangle just have a doubled hypotenuse. therefore, the bigger triangle's x and y are just the corresponding smaller triangle values doubled.
x = 6 and y = 8
Answer:
C.
Step-by-step explanation:
Recall that the sum of the (3) interior angles of a triangle <em>must</em> equate to 180.
In other words:
Where x is our unknown angle. So, we need to solve for x.
On the left, add 55 and 20:
Subtract 75 from both sides. The left side cancels:
Therefore, the third angle is 105 degrees.
Our answer is C.
Answer:
No, none of the number need to be 48 for the mean to be 48. To get a mean, you add up all the number and divide it by the amount of numbers.
Example:
the mean of 10, 79, 42, 88, 19, and 50 is 48, but the actual number 48 was not part of the set.
10 + 79 + 42 + 88 + 19 + 50 = 288
288 ÷ 6 = 48
There are 156 rows of trees altogether.
<u>Step-by-step explanation:</u>
Given that for every 11 rows of Red delicious , they plant 3 rows of Royal Gala.
Thus for 1 row of Royal Gala there would be 11/3 rows of Red delicious.
Number of rows of Royal Gala=18
For 11 rows of red delicious,they plant 7 rows of yellow delicious.
Thus for 1 row of Red delicious,there would be 7/11 rows of yellow delicious.
For 66 rows of red delicious there would be
For 11 rows of red delicious,they plant 5 rows of Braeburn
for 1 row of red delicious,they would plant 5/11 rows of Braeburn.
For 11 rows of red delicious,they would plant
Total rows of trees=66+42+30+18=156
