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2 years ago

Can someone please help me with this question

Mathematics

1 answer:

anastassius [24]2 years ago

4 0

A we can eliminate y by adding the two equations

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8.7/2=q/4 what is Q and give me work plez

ZanzabumX [31]

8.7/2=q/4
multiply both sides by 4: q=8.7/2*4
multiply both sides by 2: 2q=8.7 times 4
refine the equation: 2q=34.8
multiply both sides by 10: 20q=348
Divide both sides by 20: 20q/20=348/20
refine the equation for the final answer: q=87/5

8 0

2 years ago

Help!!!! If you wanted to model movements with both of the robot's arms in the air, what function

mixas84 [53]

Answer:

f(x)=x^2

Step-by-step explanation:

if you wanted have a function where both of the robot's arms are in the air the function could be x to the power of any even number such f(x)=x^2, f(x)=x^4, f(x)=x^6, or even f(x)=x^10. And you could still do the same transformations with these equations.

3 0

3 years ago

Shapes that have no right angles also have no perpendicular segments

nignag [31]

Answer:

Correct

Step-by-step explanation:

4 0

2 years ago

The equation $x + {y = 2 can be rewritten in a form that reveals the y-intercept of the graph of the equatior

SSSSS [86.1K]

Answer:

$y = \frac{2}{z} - \frac{x}{z}$

Step-by-step explanation:

Given

$x + zy = 2$

Required

Rewrite to show y-intercept

We have: $x + zy = 2$

Subtract x from both sides

$zy = 2-x$

Divide both sides by z

$y = \frac{2}{z} - \frac{x}{z}$

<em>The y intercet is: </em> $\frac{2}{z}$ <em></em>

7 0

2 years ago

The Wall Street Journal reported that automobile crashes cost the United States $162 billion annually (2008 data). The average c

ivanzaharov [21]

Answer:

$n=(\frac{2.326(500)}{120})^2 =93.928 \approx 94$

So the answer for this case would be n=94 rounded up to the nearest integer

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma= 500$ represent the population standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =120 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The confidence2 level is 98% or 0.98 then the significance level would be $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , the critical value for this case would be $z_{\alpha/2}=2.326$ , replacing into formula (b) we got:

$n=(\frac{2.326(500)}{120})^2 =93.928 \approx 94$

So the answer for this case would be n=94 rounded up to the nearest integer

8 0

3 years ago