![\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh\qquad \begin{cases} B=\textit{area of the base}\\ h=height \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20pyramid%7D%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B1%7D%7B3%7DBh%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AB%3D%5Ctextit%7Barea%20of%20the%20base%7D%5C%5C%0Ah%3Dheight%0A%5Cend%7Bcases%7D)
now, the first one, on the far-left.... can't see the height.. but I gather you do, now as far as its Base area, well, the bottom is just a 12x12 square, so the area of its base is just 12*12
now, the middle pyramid, has a height of 6, the base is also a square, 8x8, so the Base area is just 8*8
now the last one on the far-right
has a height of 8, the Base is a Hexagon, with sides of 6
It depends on what shape you are trying to find the volume of, but Volume= Base x Height or V=(Base)(Height)
We are given the function:
![h(t)=-16 t^{2} +4624](https://tex.z-dn.net/?f=h%28t%29%3D-16%20t%5E%7B2%7D%20%2B4624)
In order to find out <span>when will the sunglasses hit the ground we need to solve this function for t.
We start by moving t to the left side and everything ele to the right side:
</span>
![16 t^{2} =4624](https://tex.z-dn.net/?f=16%20t%5E%7B2%7D%20%3D4624)
Now we divide with 16:
![t^{2} =289](https://tex.z-dn.net/?f=t%5E%7B2%7D%20%3D289)
Now we take square root:
![t_{1} = 17s \\ t_{2} = -17s](https://tex.z-dn.net/?f=%20t_%7B1%7D%20%3D%2017s%20%5C%5C%20%20t_%7B2%7D%20%3D%20-17s)
We ignore negative solution as time can not have negative value.
It twill take 17s seconds for the sunglassesto hit the ground.
Answer:
the number is 10.
Step-by-step explanation:
2(x + 7) = 3(x - 8)
2x + 14 = 3x - 24
2x = 3x -10
x = 10