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alexandr402 [8]
3 years ago
10

How can estimating be helpful

Mathematics
1 answer:
nadezda [96]3 years ago
6 0
It helps you narrow down to a smaller answer for example there is pi, (3.14159265359) and there is more and more to that number. It is now estimated to 3.14 because it would be almost impossible to work with pi if it wasn't estimated
You might be interested in
The functions f(x) and g(x) are described below:
sesenic [268]

Suppose that the <u>function</u> f(x) is the <u>parrent</u> function and the<u> graph</u> of the function g(x)=f(x)-a can be obtained from the graph of the parrent function f(x) by <u>shifting down</u> a units.

Rewrite the expression for the function g(x) in the following way:

g(x)=32x-9=32x+8-8-9=32x+8-17=f(x)-17.

This shows that the shift down is made by 17 units.

Answer: 17 units

4 0
3 years ago
Read 2 more answers
Suppose each of the following data sets is a simple random sample from some population. For each dataset, make a normal QQ plot.
adell [148]

Answer:

a) For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

b) For this case the data is skewed to the left and we can't assume that we have the normality assumption.

c) This last case the histogram is not symmetrical and the data seems to be skewed.

Step-by-step explanation:

For this case we have the following data:

(a)data = c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

We can use the following R code to get the histogram

> x1<-c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

> hist(x1,main="Histogram a)")

The result is on the first figure attached.

For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

(b)data = c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> x2<- c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> hist(x2,main="Histogram b)")

The result is on the first figure attached.

For this case the data is skewed to the left and we can't assume that we have the normality assumption.

(c)data = c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> x3<-c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> hist(x3,main="Histogram c)")

The result is on the first figure attached.

This last case the histogram is not symmetrical and the data seems to be skewed.

7 0
3 years ago
Help with my geometry homework pleaseeee
anastassius [24]

Answer:

y=1, x=1

Step-by-step explanation:

This is a 90-45-45 triangle. One side is a sq root 2, and the other sides are a and a.

For example, if one side was 3 sq root two, then the other sides would be 3 and 3

6 0
3 years ago
(-9, -5) and (-1, -9)<br> find the midpoint
irga5000 [103]

Answer:

(-5,-7)

Step-by-step explanation:

6 0
2 years ago
In a package of 25 colored pencils 8 are red , if you bought 125 pencils how many would be red
lora16 [44]
125=5 packets of pencils
each package contains 8 red 
5 packages contain 5×8=40
In 125 pencils 40 are red.
5 0
3 years ago
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