The value of
exists 1061208.
<h3>How to estimate the value of

?</h3>
Let us rewrite
as 
Now utilizing the identity
, we get
a = 100 and b = 2 then substitute the values of a and b then
![(100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)]](https://tex.z-dn.net/?f=%28100%2B2%29%5E3%3D100%5E3%2B2%5E3%2B%5B%283%5Ctimes100%5Ctimes2%29%28100%2B2%29%5D)
= 1000000 + 8 + (600 × 102)
= 1000000 + 8 + 61200
= 1061208
Hence, 
Therefore, the value of
exists 1061208.
To learn more about cubic polynomial equation refer to:
brainly.com/question/28181089
#SPJ9
None of these are correct, however of the ones you listed, A would be the most likely to be correct. y is greater than 3... therefore making y a number greater than zero.
Answer:
Jim will be paid $150 or 30% to his account.
Step-by-step explanation:
Have a great day :)
I think that the answer is 3x/2yz^3 because I did [(27x^2y^4/16yz^4)*(8z/9xy^4)].