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Elina [12.6K]
3 years ago
10

The diagonal of a square is 27 cm long. The diagonal of a smaller square is 12 cm long. What is the difference between the lengt

hs of these two diagonals?
Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

length of big square

\sqrt{27}  = 5.2

length of small square

\sqrt{12 }  = 3.5

difference between length of two square

=5.2-3.5

=1.7

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Iris wants to buy sneakers at $15 each and high heels at $30 each. Write an algebraic expression to find the total cost of the s
kogti [31]

Answer: 30y + 15x

If x is for sneakers, and y is for high heels, plug 15 in for a and 30 in for b. This means that x is how many sneakers she buys, and y is how many high heels she buys. The equation altogether represents the total amount of her purchases.

5 0
3 years ago
A bank loaned out $8200, part of it at a rate of 7.9% per year and the rest of it at a rate of 7.4% per year. The total amount o
Lady bird [3.3K]

The amount that the bank loaned out at 7.9% is $1,574.00

How do represent the amounts lent at different rates?

On the assumption that x amount was loaned at 7.9% and that the remaining amount, (8,200-x) was loan out at 7.4%, we can determine the interest charged on each loan as the loan multiplied by the interest rate

interest on 7.9% loan=7.9%*x=0.079x

interest on 7.4% loan=7.4%*(8200-x)

interest on 7.4% loan=606.80-0.074x

total interest=0.079x+606.80-0.074x

total interest=0.005x+606.80

total interest on loans=614.67

614.67=0.005x+606.80

614.67-606.80=0.005x

7.87=0.005x

x=7.87/0.005

x=amount loaned at 7.9%=$1,574.00

y=$8200-$1574

y=$6,626.00

Find out more about bank loan interest rate on:brainly.com/question/20796174

#SPJ1

3 0
1 year ago
If rx – st = r, which expression represents r.
statuscvo [17]

Answer:

{ \tt{rx - st = r}}

» Collect like terms, r terms on the left hand side by subtracting r from both sides and adding st to both sides

{ \tt{(rx - st) { \green{ - r + st }} = r{ \green{ - r + st}}}} \\ { \tt{rx - r = st}}

» On the left hand side, factorise out r

{ \tt{ \green{r(x - 1)} = st}} \\  \\ { \boxed{ \tt{ \blue{ \: r =  \frac{st}{x - 1} }}}}

5 0
2 years ago
The polygons are regular polygons. Find the area of the shaded region.
Serga [27]
Polygon area = [circumradius^2 * # sides * sine (360/# sides)] / 2
small hexagon area =[5^2 * 6 * sine (60)] / 2
small hexagon area =[25 * 6 * 0.86603] / 2
<span><span>small hexagon area = 64.95225 </span> sq feet
</span>
large hexagon area =[10^2 * 6 * sine (60)] / 2
large hexagon area =[600 * 0.86603] / 2large hexagon area = <span> <span> <span> 259.809 </span></span></span>sq feet
Area of shaded region = large hexagon area -small hexagon areaArea of shaded region = <span> <span> 259.809</span> -</span>64.95225 <span>Area of shaded region = 194.85675 </span><span>sq feet
</span>
Source:http://www.1728.org/polygon.htm

6 0
3 years ago
What describes a regular octagon
Triss [41]
All sides and angles are congruent 
6 0
3 years ago
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