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LenaWriter [7]
3 years ago
15

CAN SOMEONE HELP MEE

Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

11.45

Step-by-step explanation:

the circumference is 36 so divide it by pie then rounded it to the nearest hundredths place

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Jerome bought 2 adult tickets and 7 student tickets for a play.How much did he spend?Show any equations used.Ticket pricesStuden
Stels [109]

From the information given,

Students ticket = $4

Adult ticket = $6

Let student ticket be x, and adult ticket be y.

This means;

\begin{gathered} Cost=2y+7x \\ C=2(6)+7(4) \\ C=12+28 \\ C=40 \end{gathered}

ANSWER:

The calculations show that Jerome spent a total of $40

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1 year ago
Check image giving brainliest to first correct answer
Snowcat [4.5K]

Answer:

<em>7</em>

Step-by-step explanation:

<em>S</em><em>o</em><em>:</em><em>a</em><em>=</em><em>3</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>b</em><em>=</em><em>(</em><em>-</em><em>2</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>c</em><em>=</em><em>2</em>

<em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>e</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>n</em><em>u</em><em>m</em><em>b</em><em>e</em><em>r</em><em>s</em><em> </em><em>i</em><em>n</em><em>t</em><em>o</em><em> </em><em>e</em><em>a</em><em>c</em><em>h</em><em> </em><em>letters</em>

<em> </em><em>s</em><em>o</em><em> </em><em>a</em><em> </em><em>i</em><em>s</em><em> </em><em>r</em><em>e</em><em>p</em><em>r</em><em>e</em><em>s</em><em>e</em><em>n</em><em>t</em><em>e</em><em>d</em><em> </em><em>b</em><em>y</em><em> </em><em>3</em><em>,</em><em>c</em><em> </em><em>b</em><em>y</em><em> </em><em>2</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>b</em><em> </em><em>-</em><em>2</em>

<em> </em><em>t</em><em>h</em><em>e</em><em>r</em><em>e</em><em>f</em><em>o</em><em>r</em><em>e</em><em> </em><em>g</em><em>i</em><em>v</em><em>i</em><em>n</em><em>g</em><em> </em><em>u</em><em>s</em><em>:</em><em> </em><em> </em><em> </em><em> </em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em><em>+</em><em>(</em><em>-</em><em>2</em><em>)</em><em>=</em><em>9</em><em>+</em><em>(</em><em>-</em><em>2</em><em>)</em><em>=</em><em>7</em>

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2 years ago
What is 1/5 expressed as a percent? A. 10% B. 20% C. 30% D. 50%
Serggg [28]

Answer:

I'm pretty sure it's B.20%

8 0
2 years ago
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What is the area of the shaded region?​
IRINA_888 [86]
20 because of the whole is 40 and the shaded part is by 20 you just take half of 40 and you get 20
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3 years ago
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Answer with  explanation:

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i.e. H_0:\mu \geq200,\ \ \ H_a:\mu

The 90% confidence interval on the mean collected amount was reported as ($190.25, $250.75) .

I recommend that we can be 90% sure that the true mean collected amount  lies in ($190.25, $250.75).

Also, $200 lies in it such that it is more far from $250.75 than $190.25, that means there are large chances of having an average is at least $200 per customer.

8 0
2 years ago
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