All categories

3 years ago

Math help owo pls will reword #_# pleath

Mathematics

2 answers:

timama [110]3 years ago

8 0

Question 13: The answer is D

Question 7: The answer is C

Question 14: The answer is B

And the question for the last Pic, the correct graph is B.

Romashka-Z-Leto [24]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Find gradient and y-intercept of Y=3x-5

NemiM [27]

Answer:

Slope m (Gradient) = 3

y-intercept: (0, -5)

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step-by-step explanation:

Step 1: Define

y = 3x - 5

Step 2: Break function

Slope m = 3

y-intercept b = -5

8 0

3 years ago

Read 2 more answers

Describe the graph of the function.y = |x – 4| – 7

juin [17]

This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:

(x-4)=0 ===> x=4,

so that now you have to plot 2 functions!

For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:

|x-4| = -(x-4)=4-x
Then:

for x<=4, y = -x+4-7 = -x-3

for x=>4, (x-4) is positive, so no changes:

y= x-4-7 = x-11,

Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11

In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:

x=4 and x= 3 for y=-x-3

And just x=5 for y=x-11

The reason is that the absolute value is continuous, so x=4 works for both:

x=4===> y=-4-3 = -7

x==4 ====> y = 4-11=-7!

abs() usually have a cusp int he point where it is =0

Hope it helps, despite being this long!

3 0

3 years ago

Read 2 more answers

Select the statements that are true for the graph of y=(x+2)^2+4

likoan [24]

Alrigty

in form
$y=a(x-h)^2+k$
the vertex is (h,k)
the constant, a, deterimines the size and direction
if a>0, then the parabola opens up and the vertex is the minimum
if a<0 then the parabola opens down and the vertex is the maximum

so we are given
$y=1(x-(-2))^2+4$
1>0 so it opens up
vertex is (-2,4)
the vertex is a minimum

the vertex is (-2,4) and the graph has a minimum

3 0

3 years ago

Read 2 more answers

Which of the following measurements results in the largest circle?

AnnZ [28]

Answer:

Step-by-step explanation:

A) r = 8

B) r = 4

C) r = $\sqrt{\frac{30}{\pi } }$ ~ 3.09