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MariettaO [177]

3 years ago

6

mr. turkowski bought 4 boxes of envelopes at the office supply store. each box has 500 envelopes. how many envelopes did mr. tur

kowski buy?

2 answers:

juin [17]3 years ago

8 0

Answer:

2000 envelopes

Step-by-step explanation:

Number of boxes bought by Mr. Turkowski at office supply store= 4 boxes

Number of envelopes in each box= 500 envelops

We have to find total number of envelopes in 4 boxes

Total number of envelopes in 4 boxes = Number of boxes × number of envelopes

Total number of envelopes in 4 boxes =4×500

Total number of envelopes in 4 boxes= 2000 envelopes

Hence, the correct answer is 2000 envelopes

jonny [76]3 years ago

7 0

You multiply 4 x 500 which equals 2,000

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Write the expanded form of the expression. <br> -1/2 (y - x) = ?

morpeh [17]

Answer:

The expanded form of the expression $-\frac{1}{2}(y-x)$ is $\mathbf{-\frac{1}{2}(y)+\frac{1}{2}(x)}$

Step-by-step explanation:

We need to write expanded form of the expression $-\frac{1}{2}(y-x)$

For expansion we will use distributive property of multiplication over addition

$a(b+c)=ab+ac$

Applying above rule:

$-\frac{1}{2}(y-x)\\=-\frac{1}{2}(y)-(-\frac{1}{2}(x))\\=-\frac{1}{2}(y)+\frac{1}{2}(x)$

So, the expanded form of the expression $-\frac{1}{2}(y-x)$ is $\mathbf{-\frac{1}{2}(y)+\frac{1}{2}(x)}$

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3 years ago

For every 1 out of 6 miles that a ship travels north it travels 3 out of 5 miles west .how many miles does the ship travel north

Oksi-84 [34.3K]

Answer:

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Step-by-step explanation:

8 0

3 years ago

-40-2(3m+1/2)=7m-2<br> Solve for m please<br> Thank you.

Anvisha [2.4K]

Answer:

{-3}

Step-by-step explanation:

Раскроем скобки:

- 40 - 6m - 1 = 7m - 2

Перенесем все, что с m, в левую часть:

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m = -3

4 0

2 years ago

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It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

3 years ago

This is due in 10 minutes help!!!!!

Paul [167]

Answer:

option 1

<h3>10</h3>

Step-by-step explanation:

using distance formula

=> root{ ( x2 - x1)² + (y2-y1)²}

=> root {(-5-1)² + (2+6)²}

=> root {(-6)² + (8)²}

=> root {36 + 64}

=> root {100}

=> 10 units

3 0

3 years ago

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