Question

Consider the following cumulative probability distribution.

Answer 1

The solution  $P(x \leq 4),p{x= 3), p(2 \leq * \leq 4)$  is mathematically given as

• $P(2 \leq X \leq 4)=0.84$
• P(X=3)= 0.17

• $P(2 < =X\leq 4)=0.53$

What is the solution $P(x \leq 4),p{x= 3), p(2 \leq * \leq 4)$?

Generally, the equation for the Probability of P(X=3) is mathematically given as

b)

$P(X=3) = P(X \leq 3)-P(X\leq 2)$

Therefore

$P(X=3)= 0.65-0.48$

P(X=3)= 0.17

c)

$P(2\leq X\leq 4) = P(X\leq 4)-P(X\leq 1)\\\\\\P(2\leq X\leq 4) = 0.84-0.31'$

$P(2 < =X\leq 4)=0.53$

a)

$P(2\leq X\leq 4)=0.84$

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