All categories

2 years ago

Consider the following cumulative probability distribution.

Mathematics

1 answer:

Marat540 [252]2 years ago

7 0

The solution $P(x \leq 4),p{x= 3), p(2 \leq * \leq 4)$ is mathematically given as

$P(2 \leq X \leq 4)=0.84$
P(X=3)= 0.17

$P(2 < =X\leq 4)=0.53$

<h3>What is the solution $P(x \leq 4),p{x= 3), p(2 \leq * \leq 4)$ ?</h3>

Generally, the equation for the Probability of P(X=3) is mathematically given as

$P(X=3) = P(X \leq 3)-P(X\leq 2)$

Therefore

$P(X=3)= 0.65-0.48$

P(X=3)= 0.17

$P(2\leq X\leq 4) = P(X\leq 4)-P(X\leq 1)\\\\\\P(2\leq X\leq 4) = 0.84-0.31'$

$P(2 < =X\leq 4)=0.53$

$P(2\leq X\leq 4)=0.84$

Read more about cumulative probability distribution.

brainly.com/question/19884447

#SPJ1

You might be interested in

A quantity and its 2/3 are added together and from thesum 1/3 of the sum is subtracted, and 10 remains.What is the quantity?

musickatia [10]

Answer:

$14\frac{1}{3}$

Step-by-step explanation:

Let's write this out as an equation. Let the unknown quantity be x:

$x+\frac{2}{3} - \frac{1}{3} (x+\frac{2}{3}) = 10\\\\3x+2-x -\frac{2}{3} = 30\\\\9x+6-3x-2=90\\\\6x= 86\\\\x = \frac{86}{6} =\frac{43}{3} =14\frac{1}{3} \\$

6 0

3 years ago

Read 2 more answers

Find irrational number between 5, 25 and 5, 26

iragen [17]

Answer:

The answer is 2.5135145

Step-by-step explanation:

The irrational number between 5,25 and 5,26
2.5135145...
The number is non-terminating and non-recurring. Hence, it is an irrational number.
A real number that cannot be expressed as a simple fraction is called an irrational number.
It is impossible to express in terms of a ratio.
If N is irrational, it is not equal to p/q, where p and q are integers and q is not equal to 0.
Example: √2, √3, √5, √11, √21, π(Pi) are all irrational.

5 0

2 years ago

Help please !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

SpyIntel [72]

Hang in there just a sec

4 0

3 years ago

Convert 22.6 square centimeters to square inches ( to the nearest hundredth).

gulaghasi [49]

Its would have to be 3.50

8 0

3 years ago

Read 2 more answers

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Mkey [24]

For this case, we have to:

By definition, we know:

The domain of $f (x) = \sqrt [3] {x}$ is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.

So, we have:

$y = \sqrt [3] {x-2}$ with $x = 0$ : $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x+2}$ with $x = 0:\ y = \sqrt [3] {2}$ is also defined.

$f (x) = \sqrt {x}$ has a domain from 0 to ∞.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x+2}$ if it is defined for $x = 0$ .

Answer:

$y = \sqrt {x-2}$

Option b

6 0

3 years ago