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3 years ago

How much would $300 invested at 4% interest compounded monthly be

Mathematics

1 answer:

7nadin3 [17]3 years ago

7 0

Answer:

To find the simple interest, we multiply 300 × 0.04 × 8 to get that:

The interest is: $96.00

You might be interested in

Find sin3A, cos<br> 3A and tan 3A when sin=1/2<br>

Slav-nsk [51]

Answer:

Sin 3A = 1

cos 3A = 0

tan 3 A = undefined

Step-by-step explanation:

$\sin A = \frac{1}{2} \\ \therefore \: \sin A = \sin \: 30 \degree.. \bigg( \because \: \sin \: 30 \degree = \frac{1}{2} \bigg) \\ \therefore \: A = 30 \degree \\ \\ now \\ \sin 3A =\sin (3 \times 30 \degree)= \sin \: 90 \degree = 1 \\ \\ \cos 3A =\cos (3 \times 30 \degree)= \cos \: 90 \degree = 0\\\\ \tan 3A =\tan (3 \times 30 \degree)= \tan \: 90 \degree = \infty$

4 0

4 years ago

What is the volume of the following cylinder? Do not round your answer. (Use 3.14 for π.)

vlabodo [156]

Answer:

1696.460033 u^3

Step-by-step explanation:

1. The volume formula for a cylinder is $\pi r^2h$ .

2. The radius is half of the width, So r would be 6. (12/2=6)

3. (6)^2 is 36. (6x6)

4. The height is given, which is 15.

5. Plug these numbers into the equation. It should be

$\pi (6)^2(15)$

6. This gives you your answer of 1696.460033 u^3.

8 0

3 years ago

Dave’s dog is one decade two years nine months three days old. Davis is half as old as his dog. How old is Dave?

Stells [14]

Answer:

Dave is 6 years 4months 16 days 12 hours old

Step-by-step explanation:

Age of Dave Dog = 10year( 1 decade)+ 9 months+3 days

Age of Dave=

$\frac{10year( 1 decade)+ 9 months+3 days}{2}$

= 6 years 4months 16 days 12 hours

8 0

3 years ago

Solve p+3 (show all of the steps) p=7

Anarel [89]

Answer:

Step-by-step explanation:

7 + 3 = 10

Not really that much to it lol

3 0

3 years ago

You do a study of hypnotherapy to determine how effective it is in increasing the number of hours of sleep subjects get each nig

brilliants [131]

Answer:

Confidence interval

$8.98-2.2\frac{1.29}{\sqrt{12}}=8.16$

$8.98+2.2\frac{1.29}{\sqrt{12}}=9.80$

And the margin of error would be:

$ME=2.2\frac{1.29}{\sqrt{12}}=0.819$

Step-by-step explanation:

For this case we have the followig dataset:

DATA: 8.2; 9.1; 7.7; 8.6; 6.9; 11.2; 10.1; 9.9; 8.9; 9.2; 7.5; 10.5

We can calculate the mean and the deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$\bar X= 8.98[/tex[tex]s = 1.29$

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=12-1=11$

The Confidence level is 0.95 or 95%, the value of significance is $\alpha=0.05$ and $\alpha/2 =0.025$ , and the critical value would be $t_{\alpha/2}=2.20$

Repplacing the info we got:

$8.98-2.2\frac{1.29}{\sqrt{12}}=8.16$

$8.98+2.2\frac{1.29}{\sqrt{12}}=9.80$ And the margin of error would be:

$ME=2.2\frac{1.29}{\sqrt{12}}=0.819$

7 0

3 years ago