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alexandr1967 [171]

3 years ago

5

The first aspect of the argument you must evaluate is the truth of the reasons that are being used to support a conclusion. (Poi

nts : 5)
True
False

2 answers:

Law Incorporation [45]3 years ago

8 0

- - True (A)

This is because the statement is true that The first aspect of the argument you must evaluate is the truth of the reasons that are being used to support a conclusion.

Marina86 [1]3 years ago

6 0

True because it the reasons used to support the conclusion are fake or false, then the argument is lost

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The square root of a negative number, such as StartRoot negative 144 EndRoot, is undefined. Explain why the square root of –x, S

IRINA_888 [86]

Answer:

see the explanation

Step-by-step explanation:

we have

$f(x)=\sqrt{-x}$

we know that

The radicand of the function cannot be a negative number

so

$-x\geq 0$

Solve for x

Multiply by -1 both sides

$x\leq 0$

The domain of the function f(x) is the interval -----> (-∞, 0]

The domain is all real numbers less than or equal to zero

The range of the function f(x) is the interval ----> [0,∞)

The range is all real numbers greater than or equal to zero

<em>Example</em>

For x=144

$144\leq 0$ ----> is not true

This value of x not satisfy the domain

substitute

$f(x)=\sqrt{-144}$ ----> this value is undefined

For x=-144

$-144\leq 0$ ----> is true

This value of x satisfy the domain

substitute

$f(x)=\sqrt{-(-144)}$

$f(x)=\sqrt{144}$ ----> this value is defined

therefore

The function will be undefined for all those values of x that do not belong to the interval of the domain of the function

6 0

3 years ago

Read 2 more answers

Hhhhhhhhhheeeeeeeeellllllllllllllppppppp

ELEN [110]

Answer:

Since the base is the same, we can just multiply the exponents, and when we do so we get y^6.

7 0

3 years ago

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Help pls!!! <br> If a1 = 6 and an<br> 2an-1 then find the value of a4.

Alenkinab [10]

24? I am not entirely sure but I think a4=24

Reason: if a1 equals 6 then I would like to think you would multiply 6 by 4 to get the value of a4 (I haven’t done this type of math in a while)

3 0

3 years ago

Quadratic equations and complex numbers PLEASE HELPPPP ASAP

kondor19780726 [428]

we are given

$27x^3-1=0$

we can also write it as

$(3x)^3-(1)^3=0$

now, we can use factor formula

$a^3-b^3=(a-b)(a^2+ab+b^2)$

we can use above formula

we get

$(3x)^3-(1)^3=(3x-1)((3x)^2+3x\times 1+(1)^2)$

now, we can simplify it

$27x^3-1=(3x-1)(9x^2+3x+1)$

now, we can set it to 0

$27x^3-1=(3x-1)(9x^2+3x+1)=0$

and then we can solve for x

$(3x-1)(9x^2+3x+1)=0$

$3x-1=0$

$x=\frac{1}{3}$

$9x^2+3x+1=0$

now, we can use quadratic formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can plug values

and we get

$x=\frac{-3\pm \sqrt{3^2-4\cdot \:9\cdot \:1}}{2\cdot \:9}$

$x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}$

So, we will get solution as

$x=\frac{1}{3},\:x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}$ ...............Answer

5 0

3 years ago

Write -94.65 as a mixed number.

ikadub [295]

$- 94 \times\frac{13}{20}$

3 0

3 years ago

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