From the graph, the coordinates of the cross that represent this car on the graph are ( 8, 2100).
<h3>What is the correlation coefficient?</h3>
The correlation coefficient is a measure of how similar two datasets are acting.
When the correlation coefficient comes out as -1, it means that both the datasets are negatively oppositely correlated.
One data increases and other data starts to decrease in the opposite direction.
When the correlation coefficient comes out below 0, values are negatively correlated.
The correlation shown by the graph is negative.
From the graph, the coordinates of the cross that represent this car on the graph are ( 8, 2100).
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There are 6 nickels and 14 pennies.
There are 20 total coins.
The ratio of nickels to coins is 6:20.
Both of these are divisible by 2, so we can reduce this to 3:10.
Answer:
Please take a picture and ask it again, it had failed to access it.
<em><u>Option A</u></em>
<em><u>The solution is:</u></em>

<em><u>Solution:</u></em>

We have to solve the equation f(x) = 0
Let f(x) = 0

Solve the above equation


Take square root on both sides

Thus the solution is found