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timama [110]
3 years ago
12

Use the information frompart a to write an equation representing the number of colories burned each minute while bowling. Let m

represent the number of minutes a 125-pound person bowls. Let x represent the number of calories burned.
Mathematics
1 answer:
Fofino [41]3 years ago
8 0

Answer:

To find the number of calories burned:

Find the Metabolic Equivalent of Task (MET) value of the task.

Calculate the number of calories burned per minute. (MET x body weight in kg x 3.5) / 200.

Multiply the calories burned per minute by the number of minutes of activity.

Now, as per the question, weight is 125 pounds (lb), we will convert the weight in kilogram (kg) which is 1 lb = 0.453 kg, it means 125 lb = 56.7

Now we have to find the MET,

A metabolic equivalent (MET) value is a measurement of the energy cost of a specific physical activity for a specific period of time.

For example. A MET of 1 would be roughly equivalent to a person's energy expenditure from sitting still in a room temperature and not actively digesting food.

As per the Calorie guide value of MET for bowling is 3.9

Now the overall formula is

Calorie Burn (x) = ((MET * body weight in kg * 3.5) / 200) * (Number of minutes) m

x = ((3.9*56.7*3.5)/200) * m

Finally, x = 3.87 m represents the number of calorie burned (x) while bowling m minutes.

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An elliptical culvert is 3.5 feet tall and 6 feet wide. It is filled with water to a depth of 0.95 feet. Find the width of the s
maks197457 [2]

Answer:

W_s \approx5.3

Step-by-step explanation:

From the question we are told that

Height H=3.5ft

Weight W= 6ft

Depth  D=0.95ft

Generally the equation for ellipses is given as

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

Where

b=H/2\\b=3.5/2\\Therefore\\b=1.75\\a=W/2\\a=6/2\\Therefore\\a=3\\

\frac{x^2}{3^2} +\frac{y^2}{1.75^2} =1

Generally to find y in the equation \frac{x^2}{a^2} +\frac{y^2}{b^2} =1

y=-b+d

y=-1.75+0.95

y=-0.8

Therefore

\frac{x^2}{3^2} +\frac{(0.8)^2}{1.75^2} =1

\frac{x^2}{3^2} =1-\frac{(0.8)^2}{1.75^2}

\frac{x^2}{3^2} =1-0.2089795918

X^2 =3^2(1-0.2089795918)

X^2 =7.119183674

X =\sqrt{7.119183674}

X =2.66817984

Therefore the width of the given stream is

W_s=2.66817984*2

W_s=5.33635968

W_s \approx5.3

3 0
3 years ago
What’s the answer to this?
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Answer:

It would be the first option: Last week, Rosemary walked at a faster pace.

Step-by-step explanation:

Last week, the speed was d=3h, as for this week, her speed was d=2.5h.

No one knows how many hours she walked this week so we cannot say that she walked a greater distance.

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Answer: are you sure these are correct?

Step-by-step explanation:

You would calculate the speed be doing 5000 m / 17 min, which would be 294.117647059 m/min

17 minutes is extremely fast, but this is correct.

4 0
3 years ago
I Don't get it......​
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I think you clicked on the correct answer! Correct me if I’m wrong!
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