Can someone help please. I need help asap.
1 answer:
You might be interested in
Answer:
The slope-intercept form equation of the line perpendicular to y = x + 10 and passes through point (-2, 7) is y = 2x + 11 ⇒ Not in the choices
Step-by-step explanation:
The slope-intercept form of the linear equation is y = m x + b, where
- m is the slope
- b is the y-intercept
The product of the slopes of the perpendicular lines is -1, if the slope of one is m, then the slope of the other is
- To find the slope of the perpendicular line to a given line reciprocal the slope of the given line and change its sign
∵ The equation of the given line is y = x + 10
→ Compare it with the form of the equation above
∴ m =
→ Reciprocal it and change its sign to get the slope of the ⊥ line
∴ m⊥ = 2
→ Substitute in the form of the equation above
∴ y = 2x + b
→ To find b substitute x and y in the equation by the coordinates of
a point on the line
∵ The line passes through the point (-2, 7)
∴ x = -2 and y = 7
∵ 7 = 2(-2) + b
∴ 7 = -4 + b
→ Add 4 to both sides to find b
∵ 7 + 4 = -4 + 4 + b
∴ 11 = b
→ Substitute it in the equation
∴ y = 2x + 11
The slope-intercept form equation of the line perpendicular to y = x + 10 and passes through point (-2, 7) is y = 2x + 11
<u><em>Note:</em></u> The answer is not in the choices
Answer:
see attachments
Step-by-step explanation:
A) The graph is three horizontal line segments.
Since the domain expressions all have ≤ on the left end of the interval and < on the right end, there will be a closed dot at the left end of each graph segment and an open dot at the right end.
The first segment is at y = -5 between x = -5 and x = -1.
The second segment is at y = -1 between x = -1 and x = 2.
The third segment is at y = 2 between x = 2 and x = 5.
See the first attachment for a graph.
__
B) You are given the graph for the middle segment, so you only need to graph the horizontal lines for the other two.
The first segment is a horizontal line at y = 1, extending to the left from x = -1.
The last segment is a horizontal line at y = 4, extending to the right from x = 2.
The segments of the graph connect with each other, so there is no need to indicate any discontinuities using closed/open circles.
See the second attachment for a graph.
