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charle [14.2K]
3 years ago
12

Neutrons do not enter into any ordinary electrical activity

Physics
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

Neutrons are the particles which are present in the nucleus of an atom. These have a neutral charge, means that the don't have a positive charge like proton or a negative charge like an electron, but these are far more dense than electrons and protons. Under normal reaction, neutron may seem to just exist, as usually electrons are the particles which forms bonds or breaks them.

However, Neutrons play an important role in the weight and Radioactive properties of a material. During radioactive decay, which occurs in radioactive elements, the nucleus of an atom breaks down and releases energy and matter, which is primarily due to the knocking out of a neutron. These knocked out neutrons forms the basis of the nuclear fission and fusion reactions.

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A wave has a wavelength of 5m and frequency of 5 Hz. What is the speed of the wave?​
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If you multiply m (the unit for wavelength) with 1s (the unit for frequency), you will get m/s, the unit for speed. Now multiply! 25 m/s is your final answer!
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) determine the density of a 32.5 g metal sample that displaces 8.39 ml of water.
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Density is the ratio of a substance's mass to its volume. On the other hand, according to Archimedes' principle, the volume of water displaced is equal to the volume of the object placed on the water. Thus, the density of the metal is equal to 8.39 mL. So, the density would be

Density = 32.5 g/8.39 mL = 3.87 g/mL
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4 years ago
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5. How does a jack make changing a tire easier?
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Explanation:

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How can coaches improve team performance?
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Three identical resistors are connected in parallel. The equivalent resistance increases by 630 when one resistor is removed and
strojnjashka [21]

Answer:

each resistor is 540 Ω

Explanation:

Let's assign the letter R to the resistance of the three resistors involved in this problem. So, to start with, the three resistors are placed in parallel, which results in an equivalent resistance R_e defined by the formula:

\frac{1}{R_e}=\frac{1}{R} } +\frac{1}{R} } +\frac{1}{R} \\\frac{1}{R_e}=\frac{3}{R} \\R_e=\frac{R}{3}

Therefore, R/3 is the equivalent resistance of the initial circuit.

In the second circuit, two of the resistors are in parallel, so they are equivalent to:

\frac{1}{R'_e}=\frac{1}{R} +\frac{1}{R}\\\frac{1}{R'_e}=\frac{2}{R} \\R'_e=\frac{R}{2} \\

and when this is combined with the third resistor in series, the equivalent resistance (R''_e) of this new circuit becomes the addition of the above calculated resistance plus the resistor R (because these are connected in series):

R''_e=R'_e+R\\R''_e=\frac{R}{2} +R\\R''_e=\frac{3R}{2}

The problem states that the difference between the equivalent resistances in both circuits is given by:

R''_e=R_e+630 \,\Omega

so, we can replace our found values for the equivalent resistors (which are both in terms of R) and solve for R in this last equation:

\frac{3R}{2} =\frac{R}{3} +630\,\Omega\\\frac{3R}{2} -\frac{R}{3} = 630\,\Omega\\\frac{7R}{6} = 630\,\Omega\\\\R=\frac{6}{7} *630\,\Omega\\R=540\,\Omega

8 0
3 years ago
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