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Keith_Richards [23]
3 years ago
7

How fast should the platform move, vp, for the person to detect a beat frequency of 7.00 hz ? take the speed of sound to be 344

m/s. express your answer numerically in meters per second using three significant figures. hints?
Physics
1 answer:
NeX [460]3 years ago
7 0
<span>Delta(f) =f0 * v_rel/c , where v_rel is the relative velocity between source and observer. The source is moving at a speed v but the sound bounced off the wall and the receiver is moving toward it too. So, Delta(f) = f0 (2 V) / c Hence V = c Delta(f) /(2 f0)= 344 m/s * (7.00Hz/(2*245Hz)) =4.91 m/s</span>
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Why is pure oxygen stored as a liquid under pressure
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<h2>Answer: It is highly flammable.</h2>

Explanation:

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3 years ago
An empty paper cup is the same temperature as the air in the room. A student fills the cup with cold water. Which of the followi
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Answer:

C

Explanation:

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3 years ago
A polar bear runs at a speed of 11 m/s and has a mass of 380.2 kg. How much Kinetic energy does the bear have?
Yanka [14]

Answer:

\boxed{\sf Kinetic \ energy \ of \ the \ bear (KE) = 23002.1 \ J}

Given:

Mass of the polar bear (m) = 6.8 kg

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To Find:

Kinetic energy of the polar bear (KE)

Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 380.2 \times  {11}^{2}

\sf \implies KE = \frac{1}{ \cancel{2}}  \times  \cancel{2} \times 190.1 \times 121

\sf \implies KE = 190.1 \times 121

\sf \implies KE = 23002.1 \: J

\therefore

Kinetic energy of the polar bear (KE) = 23002.1 J

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Answer:

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Given that:

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E = [18 * 10^(9-33)] ÷ 10^-24

E = (18 * 10^-24) / 10^-24

E = 18 * 10^-24+24

E = 18 * 10^0

E = 18 N/C

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