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Kitty [74]
3 years ago
11

You turn on a light and observe cockroaches scurrying to dark hiding places. wha have you observed?

Physics
2 answers:
borishaifa [10]3 years ago
7 0
You have observed cockroaches scurrying to dark hiding places when the light is turned on.
Doss [256]3 years ago
4 0
They don't want to be killed or they are hiding
You might be interested in
What is climate change? How is it caused
OleMash [197]

climate change is a change in climate in the Earth 's normal weather patterns for different climates. it normally changes little by little over the years.the earth is cooler and warming .now it's getting warmer. this phenomenon is also known by as globall warming.it's causes are:

1.energy uses

2.agriculture and land use 3.Transport 4.Industries 5.Growing demands for food and water

A greenhouses is made from glass or clear plastic. It is useful for growing plants in winter in cooler climates.

sorry i don't know last one .

The 2015 United Nations Climate Change Conference, COP 21 or CMP 11 was held in Paris, France, from 30 November to 12 December 2015.

End date: 12 December 2015

Start date: 30 November                                                                       sorry i don't know last one .

Explanation:

8 0
3 years ago
55. (III) A uniform circular plate of radius 2R has a circular hole of radius R cut out of it. The center of the smaller circle
Aleksandr [31]

Answer:

P = 0.27R from the center

Explanation:

Given,

The radius of the uniform circular plate, R = 2R

The radius of the hole, r = R

The center of the smaller circle from the center is, d = 0.8R

The center of mass of a circular disc with a hole in it given by the formula

                               P = dr²/R² - r²

Where P is the distance from the center of mass located in the line joining the two centers opposite to the hole.

Substituting the given values in the above equation,

                               P = 0.8R x R² / 4R² - R²

                                  = 0.27R³/R²

                                  = 0.27R

Hence the center of mass of plate is at a distant  P = 0.27R from the center

6 0
3 years ago
A 1000-kg car is slowly picking up speed as it goes around a horizontal curve whose radius is 100 m. The coefficient of static f
Snezhnost [94]

Answer:

18.5 m/s

Explanation:

On a horizontal curve, the frictional force provides the centripetal force that keeps the car in circular motion:

\mu mg = m\frac{v^2}{r}

where

\mu is the coefficient of static friction between the tires and the road

m is the mass of the car

g is the gravitational acceleration

v is the speed of the car

r is the radius of the curve

Re-arranging the equation,

v=\sqrt{\mu gr}

And by substituting the data of the problem, we find the speed at which the car begins to skid:

v=\sqrt{(0.350)(9.8 m/s^2)(100 m)}=18.5 m/s

7 0
4 years ago
Read 2 more answers
A particle executes simple harmonic motion with an amplitude of 3.00 cm. At what position does its speed equal half of is maximu
Mrac [35]

Answer:

x=±0.026m

Explanation:

In simple harmonic motion the maximum value of the magnitude of velocity

v_{max}=wA=\sqrt{\frac{k}{m} }A

The speed as a function of position for simple harmonic oscillator is given by

v=w\sqrt{A^{2}-x^{2}

where A is amplitude of motion

Given data

Amplitude A=3 cm =0.03 m

v=(1/2)Vmax

To find

We have asked to find position x does its speed equal half of is maximum speed

Solution

The speed of the particle the maximum speed as:

v=\frac{V_{max} }{2}\\ w\sqrt{A^{2}-x^{2}  }=\frac{wA}{2}\\  A^{2}-x^{2}=\frac{A^{2} }{4}\\ x^{2}=A^{2}- \frac{A^{2} }{4}\\ x^{2}=\frac{3A^{2}}{4} \\x=\sqrt{\frac{3A^{2}}{4}}

x=±(√3(0.03)/2)

x=±0.026m

5 0
4 years ago
A 1.90-m-long barbell has a 25.0 kg weight on its left end and a 37.0 kg weight on its right end. if you ignore the weight of th
gregori [183]

Answer: The center of gravity is 1.1338 m away from the left side of the barbell

Explanation:

Length of the barbell = 1.90 m

The distance center of gravity from left = x

Mass on the left side = 25 kg

The distance center of gravity from right = 1.90 - x

Mass on the right side = 37 kg

At the balance point: m_1x_1=m_2x_2

25 kg\times x=37 kg\times (1.90-x)

x=1.1338 m

The center of gravity is 1.1338 m away from the left side of the barbell

7 0
3 years ago
Read 2 more answers
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