Answer:
Average velocity of the function over the given interval
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Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given function y = 3/x -2 ...(i)
The average velocity of the function over the given interval
Average velocity = 
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now integrating
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by using formulas
log a-log b = log(a/b)
on simplification , we get
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Average velocity of the function over the given interval
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So anytime we have a slope and want to find the slope of a perpendicular line, we just have to remember a perpendicular line's slope is the negative reciprocal (reciprocal means flip the fraction). So if we had a slope of 3/4, the slope perpendicular to it would be - 4/3.
First we need to find our slope, to do this we take the change in y over the change in x like so:
(15-12)/(4-7) = - 3/4
The slope perpendicular to this is 4/3.
Answer:
x = i√3, -i√3
Step-by-step explanation:
Simply take the root of both sides, then solve.
Since 6 is positive, it's (x+blank)^2
6/2=3, and (x+3)^2 = x^2+6x+9. We have x^2+6x-2, so we have to add 9 to both sides to get (x+3)^2-2=9, then subtract 9 from both sides to get
(x+3)^2-11=0, or (x+3)^2=11. Square root both sides to get x+3=sqrt(11), and x=sqrt(11)-3, which is approximately 0.32
