Question

A lab technician made a 14 cm diameter hole through the middle of a cylinder that has a diameter of 20 cm and a height of 18 cm. What is the approximate volume of the finished cylinder, to the nearest tenth of a centimeter?

Answer 1

Answer:

$2,882.5\ cm^3$

Step-by-step explanation:

we know that

The approximate volume of the finished cylinder, is equal to subtract the volume of the hole from the volume of the original cylinder

so

$V=\pi r_1^{2}h-\pi r_2^{2}h$

$V=\pi h[r_1^{2}-r_2^{2}]$

where

r_1 is the radius of the original cylinder

r_2 is the radius of the hole

we have

$r_1=20/2=10\ cm$ ---> the radius is half the diameter

$r_2=14/2=7\ cm$ ---> the radius is half the diameter

$h=18\ cm$

$\pi=3.14$

substitute the given values in the formula

$V=(3.14)(18)[10^{2}-7^{2}]$

$V=56.52[51]\\V=2,882.5\ cm^3$