Considering the area of the hole, it is found that there is a 4.9% probability of hitting a ball into the circular hole.
<h3>What is the area of a circle?</h3>
The area of a circle of radius r is given by:
In this problem, the hole has a diameter of 1 ft, hence it is radius is of r = 1 ft/2 = 0.5 ft, and it's area is given by:
Hence the probability is given by:
p = 0.7854/16 = 0.049 = 4.9%
More can be learned about probabilities at brainly.com/question/14398287
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D = 25 ft is the length of a shadow. L - the length of a tree.
Two angles are 85° and 65° and the third is 180° - ( 65° + 85° ) =
= 180° - 150° = 30°.
We will use the Sine Law:
25 / sin 30° = L / sin 65°
25 / 0.5 = L / 0.9063
25 * 0.9063 = 0.5 L
22.6577 = 0.5 L
L = 22.6577 : 0.5
L = 45.3 ft.
Answer: the approximate length of the tree is 45.3 ft.
Answer:
24
Step-by-step explanation:
PEMDAS: 15-14+23
1+23
24
Answer:
I promise you this is easier than it looks, just bare with me.
You have to order these numbers from the smallest to the biggest. Now before we do this, we wanna make the fractions and mixed numbers decimals to make this easier.
5 8/11
Convert the fraction to a decimal: Divide the numerator by the denominator. (8 divide by 11).
Add this decimal number to the whole number part of the mixed number. (0.72 plus 5)
It would be 5.72
Now 57/10
The same steps as the last one, but since it isn't a mixed number you don't add anything. (57 divided by 10)
It would be 5.7
Now we have to order them from least to greatest. How do we figure that out? Well lets list the numbers that we have now:
5.72
5.7
5.67
5.726
Now since they all have the same whole number, we just have to look at the numbers after the decimal. Well the least number we have here is "7". Then it would be 67, then 72, then 726.
So the answer would be from least to greatest:
5.7
5.67
5.72
5.726
I hope this helps..sorry if I took so long I wanted to make sure I explained this as good as I can so you don't keep struggling. Good luck, take care <3
Have a good night/day (:! Much love!
Y=mx+b is the equation you want to use
