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ziro4ka [17]
3 years ago
7

When you solve a system of equations algebraically, how can you tell whether the system has zero,one,or an infinite number of so

lutions?
Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

By comparing the ratios of the coefficients, we can determine whether the system has zero,one,or an infinite number of solutions

Step-by-step explanation:

Here, let us assume the given set of equations is:

a_1x+b_1y+c_1 =  0\\a_2x+b_2y+c_2 = 0

If the system is NOT in above form, convert it in such form.

Now, there are three cases of solution in the given system.

1. The system has NO or ZERO SOLUTION

Consider the given system.

If the ratio \frac{a_1}{a_2} = \frac{b_1}{b_2}  \neq\frac{c_1}{c_2}

Then the given system of equations has NO SOLUTION.

2. The system has EXACTLY ONE SOLUTION

Consider the given system.

If the ratio \frac{a_1}{a_2} \neq \frac{b_1}{b_2}

Then the given system of equations has UNIQUE SOLUTION.

3. The system has INFINITELY MANY SOLUTION

Consider the given system.

If the ratio \frac{a_1}{a_2} = \frac{b_1}{b_2}  = \frac{c_1}{c_2}

Then the given system of equations has INFINITELY MANY SOLUTION.

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madreJ [45]

Answer: y3 -8y2 + 5 (d.)

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3 0
4 years ago
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AlekseyPX

Answer:

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Step-by-step explanation:

8 0
3 years ago
Which correctly represents the inequality 10x+18&lt;-2<br><br> PLSS
77julia77 [94]

Answer:

see below

Step-by-step explanation:

10x+18<-2

Subtract 18 from each side

10x+18-18<-2-18

10x < -20

Divide by 10

10x/10 < -20/10

x < -2

7 0
3 years ago
3. A ball was thrown into the air with an initial velocity of 72 feet per second. The height of the
timurjin [86]

Answer:

A. The maximum heigh is 81 feet

B. The ball will reach the maximum heiight at 2.25 seconds

C. The domain of the function is t\in [0,4.5]

D. The range of the function is h(t)\in [0,81]

E. 4.5 seconds

Step-by-step explanation:

A ball was thrown into the air with an initial velocity of 72 feet per second. The height of the ball after t seconds is represented by the equation:

h= -16t^2 + 72t

The maximum height will be at parabola's vertex. Find it:

t_v=\dfrac{-b}{2a}\\ \\t_v=-\dfrac{72}{2\cdot (-16)}=\dfrac{72}{32}=\dfrac{9}{4}=2.25\\ \\h(t_v)=-16\cdot t_v^2+72\cdot t_v\\ \\h(2.25)=-16\cdot 2.25^2+72\cdot 2.25=81

A. The maximum heigh is 81 feet

B. The ball will reach the maximum heiight at 2.25 seconds

C. Find where the parabola intersects the x-axis:

h=0\Rightarrow -16t^2+72t=0\\ \\t(-16t+72)=0\\ \\t_1=0\ \text{or}\ 16t=72,\ t_2=\dfrac{9}{2}=4.5

So, the domain of the function is t\in [0,4.5]

D. The range of the function is

h(t)\in [0,81]

E. The ball is at the air for 4.5 seconds

4 0
4 years ago
What is the positive solution to the equation 0 = –x2 + 2x + 1? Quadratic formula: x = StartFraction negative b plus or minus St
Vladimir [108]

Answer:

See attached for a "Neat" quadratic formula.

a = -1

b = 2

c = 1

x = [-2 +- sqr root( 4 -4*-1*1)] / -2

x = [-2 +- sqr root( 4 -4*-1*1)] / -2

x = [-2 +- sqr root(8)] / -2

x1 = (-2 +2.8284271247)  / -2

x1 = .8284271247 / -2

x1 = -0.41421

x2 = (-2 -2.8284271247)  / -2

x2 = ( -4.8284271247)  / -2

x2 = 2.4142135624

So the equation has the positive solution of

2.4142135624

Step-by-step explanation:

3 0
3 years ago
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