For questions 1-3 select which relation is a function.

after spending 80% of her daily allowance, Ola found out she had 25k left. How much was her total allowance?

Anestetic [448]

Answer:

31.25 k

Step-by-step explanation:

80 % * x = 25 k

.80 x = 25 k

x = 25 k / .80 = 31.25 k

8 0

2 years ago

A state offers two lottery games, WinOne and PlayBall. Both games cost $2 per ticket.

uysha [10]

In this question, both tickets cost 2$ per ticket.
The answer to this question would be: $0

In WinOne scenario, you need to match a ticket that has to pick from A-J(10 possibilities) and 0-9 (10 possibilities). The chance to win would be: 1/10* 1/10= 1/100

The expected value must be:
E= chance to win * win amount - ticket price
E= 1//100*$200 - $2= $2-$2= 0

8 0

3 years ago

At a carnival game, you randomly throw two darts at the board and break two balloons. What is the probability that both the ball

Amanda [17]

4/15 of the balloons are purple. You have two darts. There are 105 combinations of hitting two balloons out of the 15. There are 6 combinations of purple balloons to be hit. This (Purple combinations over total combinations) is your probability. 6/105 simplified to 2/35 or 2:35
So your chance of picking the purple balloons, both purple, out is 2 in 35 or 2/35
Brainliest?

6 0

3 years ago

X+5/2=10 linear equations step by step explantion

Vera_Pavlovna [14]

See attachment for math work and answer.

6 0

3 years ago

A data set lists weights (lb) of plastic discarded by households. The highest weight is 5.31 lb, the mean of all of the weight

a_sh-v [17]

Answer:

a) The difference is of 3.222 lbs.

b) 1.64 standard deviations.

c) Z = 1.64

d) Not significant, as the z-score of 1.64 is between -2 and 2.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of all of the weights is x=2.088 lb, and the standard deviation of the weights is s=1.968 lb.

This means that $\mu = 2.088, \sigma = 1.968$

a. What is the difference between the weight of 5.31 lb and the mean of the weights?

This is $X - \mu = 5.31 - 2.088 = 3.222$

The difference is of 3.222 lbs.

b. How many standard deviations is that [the difference found in part (a)]?

This is the z-score. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.31 - 2.088}{1.968}$

$Z = 1.64$

1.64 standard deviations.

c. Convert the weight of 5.31 lb to a z score.

Z = 1.64, as found above.

d. If we consider weights that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the weight of 5.31 lb significant?

Not significant, as the z-score of 1.64 is between -2 and 2.

5 0

3 years ago