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3 years ago

How to write (4f - 3 + 2g) - (-4g + 2) in standard form.

Mathematics

1 answer:

ANTONII [103]3 years ago

8 0

Answer:

4f-5+6g

Step-by-step explanation:

Standard Form:4f-5+6g

(4f - 3 + 2g) - (-4g + 2) REMOVE PARENTHESIS

4f-3+2g+4g-2 CALCULATE AND COMBINE LIKE TERMS

SOLUTION:4f-5+6g

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Paul got a ping pong table for his birthday. It measures 2x − 3 feet by 3x +2 feet. He is looking to purchase a cover. Which of

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6x2 − 5x − 6 square feet

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3 years ago

Let φ(x, y) = arctan (y/x) .

Alexandra [31]

Answer:

a) $\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

b) $\large \mathbb{R}^2-\{(0,0)\}$

c) the points of the form (x, -x) for x≠0

Step-by-step explanation:

If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be

$\large F(x,y)=(\frac{\partial \phi}{\partial x},\frac{\partial \phi}{\partial y})$

On one hand we have,

$\large \frac{\partial \phi}{\partial x}=\frac{\partial arctan(y/x)}{\partial x}=\frac{-y/x^2}{1+(y/x)^2}=-\frac{y/x^2}{1+y^2/x^2}=\\\\=-\frac{y/x^2}{(x^2+y^2)/x^2}=-\frac{y}{x^2+y^2}$

On the other hand,

$\large \frac{\partial \phi}{\partial y}=\frac{\partial arctan(y/x)}{\partial y}=\frac{1/x}{1+(y/x)^2}=\frac{1/x}{1+y^2/x^2}=\\\\=\frac{1/x}{(x^2+y^2)/x^2}=\frac{x}{x^2+y^2}$

$\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

The domain of definition of F is

$\large \mathbb{R}^2-\{(0,0)\}$

i.e., all the plane X-Y except the (0,0)

Here we want to find all the points such that

$\large (-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})=(k,k)$

where k is a real number other than 0.

But this means

$\large -\frac{y}{x^2+y^2}=\frac{x}{x^2+y^2}\Rightarrow y=-x$

So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0

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3 years ago

Jean can swim 100 meters in 1.86 minutes. Sean can swim the same distance in 2.12 minutes.

ELEN [110]

please where is the question

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2 years ago

What is the area of a circle with a diameter of 9.2 centimeters? Round your answer ro the nearest hundredth.

nika2105 [10]

The answer the the problem is A.

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3 years ago

Henry's patio is in the shape of a rectangle. He said the perimeter of the patio is 48 feet . He knows that one side is 9 feet w

ss7ja [257]

Answer:

2 sides of the patio are 9ft and another 2 sides are 15ft

Step-by-step explanation:

To solve this problem we have to know thata rectangle has 4 sides and 2 of them are equal to each other

This is the formula to calculate perimeter

p = perimeter 48 ft

a = side a = 9 ft

b = side b

p = 2a + 2b

we replace the known values

48ft = 2*9ft + 2b

48ft = 18ft + 2b

48ft - 18ft = 2b

30 / 2 = b

15 = b

2 sides of the patio are 9ft and another 2 sides are 15ft

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3 years ago