Question

Print 'userNum1 is negative" if userNum1 is less than 0. End with newline Convert userNum2 to 0 if userNum2 is greater than 9. Otherwise, print "userNum2 is less than or equal to 9:. End with newline 3 int main(void) 4 int userNuml; S int userNum2; 6 7 userNum1-1; 8 userNum2 7 10 if (userNum1) printf "userNum1 is negative.n 12 13 if(userNum2-9 14 15 16 17 print f("userNum2 18 19 return ; printf("userNum2 is less than or equal to 9.\n; Your solution goes here is%d.\n", use rNur?); 20 Check Try again x A possible solution uses an if statement for userNum1, and an if-else statement for userNum2 x Testing for correct output for userNum 1 = 0 and userNum2 = 10 Output differs.

Answer 1

Answer:

#include <stdio.h>

int main()

{

   int userNum1;

   int userNum2;

   

   userNum1 = -1;

   userNum2 = 7;

   

   if (userNum1 < 0)

       printf("userNum1 is negative. \n");

       

   if(userNum2 > 9)

       userNum2 = 0;

   else

       printf("userNum2 is less than or equal to 9.\n");

   return 0;

}

Explanation:  

Initialize userNum1 and userNum2.

If userNum1 is less than 0, print 'userNum1 is negative" and end with newline.

if userNum2 is greater than 9, assign 0 to userNum2.

Otherwise, print "userNum2 is less than or equal to 9 and end with newline.