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Fudgin [204]
3 years ago
15

How do you change negative 33/165 into simplest form

Mathematics
1 answer:
juin [17]3 years ago
5 0
Divide 165 by 33. Your end answer result should be 1/5 or 20%.
Hope this helps.
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What is the solution to the following equation? (4 points) 5(2x − 6) + 20 = 10 Group of answer choices
vichka [17]

Answer:

x=2

Step-by-step explanation:

6 0
3 years ago
Find the distance between the points (a, 0) and (0, b).
katrin [286]
The answer is c because the a and b work together to combined a like for
7 0
2 years ago
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side
lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

       =cot x (sec²x)²

       =cot x (1+tan²x)²     [ ∵ sec²x=1+tan²x]

       =  cot x(1+ 2 tan²x +tan⁴x)

       =cot x+ 2 cot x tan²x+cot x tan⁴x

        =cot x +2 tan x + tan³x        [ ∵cot x tan x =\frac{ \textrm{tan x }}{\textrm{tan x}} =1]

       =R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

 L.H.S =(sin x)(tan x cos x - cot x cos x)

          = sin x tan x cos x - sin x cot x cos x

           =\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}

           = sin²x -cos²x

           =1-cos²x-cos²x

           =1-2 cos²x

           =R.H.S

         

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

         =1+\frac{{sin^2x}}{cos^2x}                       [\textrm{sec x}=\frac{1}{\textrm{cos x}}]

         =1+tan²x                        [\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]

         =sec²x

        =R.H.S

4.

\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}

L.H.S=\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}

       =\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}

      =\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}

     =\frac{\textrm{2sin x}}{sin^2 x}

      = 2 csc x

    = R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

        = sec²x-tan²x

        =\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}

        =\frac{1- sin^2x}{cos^2x}

        =\frac{cos^2x}{cos^2x}

        =1

     

       

8 0
3 years ago
Write
Schach [20]

Answer:

y+3=4(x-5)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-3)=4(x-5)

y+3=4(x-5)

5 0
3 years ago
Find the equation of the line that passes thru (-1,-5) and is parallel to 3x+y=-5. Show work.
sertanlavr [38]

Answer:

y=-3x-8

Step-by-step explanation:

slope-intercept form:

y=mx+b

Start with the given equation, and to find the slope, convert it to slope-intercept form by solving for y.

3x+y=-5

In this case, all you need to do is subtract 3x from both sides.

y=-3x-5

Here, the slope is -3. The slope of a parallel line will also be -3.

Now, we have 3 known variables. We have the slope and the x and y of a known point. Use those 3 knowns to solve for the 1 unknown, the y-intercept.

y=mx+b\\-5=(-3)(-1)+b\\-5=3+b\\-8=b\\b=-8

Finally, with the slope and the y-intercept, you can write the equation of the line:

y=-3x-8

3 0
3 years ago
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