Answer:
Number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Explanation:
Lowest four digit positive integer = 1000
Highest four digit positive integer less than 4000 = 3999
We know that multiples of 5 end with 0 or 5 in their last digit.
So, lowest four digit positive integer which is a multiple of 5 = 1000
Highest four digit positive integer less than 4000 which is a multiple of 5 = 3995.
So, the numbers goes like,
1000, 1005, 1010 .....................................................3990, 3995
These numbers are in arithmetic progression, so we have first term = 1000 and common difference = 5 and nth term(An) = 3995, we need to find n.
An = a + (n-1)d
3995 = 1000 + (n-1)x 5
(n-1) x 5 = 2995
(n-1) = 599
n = 600
So, number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Answer:
Yes,
Step-by-step explanation:
because two sides are shown equal to each other, a and b. Also two angles are equal to each other, x and y. Once you know two angles or two sides are equal so is the third side.
Another way is SAS (side angle side). There is side a, angle y, and side b. These are shown on both triangles.
Therefore, we can conclude these two triangles are congruent.
Y-intercept 168
x-intercept (-21)
120 IS THE CORRECT ANSWER. BUT THIS IS NOT FOR SURE!
Answer:
because when the value of x is replaced in the factorisation it Will be equivalent to 100
