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7nadin3 [17]
4 years ago
7

The cost of tickets varies directly with the number of tickets. Suppose 7 tickets cost $126. How much would

Mathematics
2 answers:
olga55 [171]4 years ago
5 0
The correct answer is $216 because when 7 tickets cost $126 each ticket was $18. I know this because 126/7 is 18. Now to find out how much 12 tickets cost you multiply 18x12 to get 216.
Darina [25.2K]4 years ago
5 0

Answer:

B.$216

Step-by-step explanation:

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Find the quotient<br> 4/3÷1 1/12
nlexa [21]
The answer should be 1/9

8 0
3 years ago
6-x/4=x/8<br> solve for x
mina [271]

Answer:

Hope this helps

Step-by-step explanation:

x = 16

5 0
3 years ago
Read 2 more answers
Kassie recorded the favorite sport of students at her school. She surveyed 800 students. How many more students chose Baseball t
lisov135 [29]

Answer:

40 more kids chose baseball over basketball.

Step-by-step explanation:

The best way to go about this is to use benchmark percentages.

For baseball, 25% of 800 people chose that, so we can do 800/4 to get 200, so 200 students chose baseball

For basketball, we could do 800/5 but that isn't mental math, so we can do 10% of 800 is 80 and 80*2=160. So 40 more kids chose baseball over basketball.

6 0
3 years ago
Needdd hellpppppssssssss
Ratling [72]

Answer:

Choice number one:

\displaystyle \frac{5}{10}\cdot \frac{4}{9}.

Step-by-step explanation:

  • Let A be the event that the number on the first card is even.
  • Let B be the event that the number on the second card is even.

The question is asking for the possibility that event A and B happen at the same time. However, whether A occurs or not will influence the probability of B. In other words, A and B are not independent. The probability that both A and B occur needs to be found as the product of

  • the probability that event A occurs, and
  • the probability that event B occurs given that event A occurs.

5 out of the ten numbers are even. The probability that event A occurs is:

\displaystyle P(A) = \frac{5}{10}.

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

\displaystyle P(B|A) = \frac{4}{9}.

The probability that both A and B occurs will be:

\displaystyle P(A \cap B) = P(B\cap A) =  P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}.

6 0
3 years ago
Any help towards finding out Part B and C would be greatly appreciated!
Alika [10]
Part B: I think the relation that has the greater value when x=6 is f(x) = 7x - 15 because:

7(6) - 15 = 27 which is greater than the output of 14.

Part C: the value of x would be 3 because:

f(x) = 7x - 15
6 = 7x - 15
+ 15 +15
21 = 7x
3 = x

Sorry if any of this is wrong.
6 0
4 years ago
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