Answer:
the approximate probability that the insurance company will have claims exceeding the premiums collected is 
Step-by-step explanation:
The probability of the density function of the total claim amount for the health insurance policy is given as :
Thus, the expected total claim amount 
= 1000
The variance of the total claim amount 
However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100
To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :
P(X > 1100 n )
where n = numbers of premium sold
Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is
Answer: 1 + 24x
Add numbers
1 + 2x x 3 x 4
Calculate the product
1 + 24x
Answer: b
Step-by-step explanation:
Answer:
(x, y) = (-1, -3) or (4, 12)
Step-by-step explanation:
A graphing calculator can show the solutions to this system.
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You can equate expressions for y and solve for x.
3x = x^2 -4
x^2 -3x = 4 . . . . add 4-3x
x^2 -3x +2.25 = 6.25 . . . . complete the square by adding (-3/2)^2 where -3 is the coefficient of x.
(x -1.5)^2 = 2.5^2 . . . . . . rewrite as squares
x -1.5 = ±2.5 . . . . . . . . . . take the square root
x = 1.5 ± 2.5 = -1, +4
y = 3x = -3, +12, respectively
Solutions are ...
(x, y) = (-1, -3) . . . . and . . . . (4, 12)
Add all the coins to get total coins:
6 + 8 + 12 + 3 = 29 total coins
Subtract dimes to find total of the coins that are not dimes:
29 -6 = 23
Probability of not picking a dime is the number of coins that aren’t dimes over total coins:
23/29
