Answer:
0.818335 ≤ p ≤ 0.86366
Step-by-step explanation:
Given that:
Sample size (n) = 1000
Positive lung cancer = 841
n(p) = 841, p(p) = 841/1000 = 0.841
n(1 - p) = 1000 - 841 = 159
1 - p = 0.159
95% confidence interval
For a 95% confidence interval : z = 1.96
P ± z√p(1-p) / n
0.841 ± 1.96 * √0.841(0.159) / 1000
0.841 - (1.96 * 0.0115636) = 0.818335344
0.841 + (1.96 * 0.0115636) = 0.863664656
0.818335 ≤ p ≤ 0.86366
Answer: Mrs.Buller collects a 500-ml sample of seawater for her chemistry class, and it has 1.94% of chlorine, we have to determine the amount of chlorine in the sample:
Therefore the chlorine content in 500ml of water is 9.7ml.
Answer:
x = 335 - (6 * v)
Step-by-step explanation:
In order to calculate the value remaining, we need to first multiply the daily cost of each visit by the number of visits made to the gym which is represented by the variable (v). Once we have this cost of all the days then we subtract this amount from the current account balance in order to get the new remaining balance which is represented by x.
x = 335 - (6 * v)
Answer:
c. infinitely many solutions
Step-by-step explanation:
Answer:
36 cubes
Step-by-step explanation:
the pic is up there
