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3 years ago

Solve for the variable. Include which Property you used in your work at each step

Mathematics

1 answer:

Nana76 [90]3 years ago

7 0

Answer:

d=-18

a=51

x=-4

c=13/3

Step-by-step explanation:

1. subtract 6 from both sides

divide both sides by -2

2. add 2 to both sides

times both sides by 3

3. times both sides by 4

divide both sides by 9

4. multiply the 10 out into the parenthesis add the 10c and 2c to get 12 c

add 40 to both sides

divide both sides by 3

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Plz hel p me my class is counting on me(you)

solniwko [45]

Answer:

The correct answer is D because for example...

Step-by-step explanation:

If b squared minus 4ac is non-negative, so at 0 or greater, we have at least one real solution. If it's less than 0, if it's negative, we have no real solutions!

Hope I was able to help, and I hope you Have a good day! :)

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3 years ago

The owner of a house has paid the advance water charge for three months beginning October 1. The owner sold the house, and it cl

Maru [420]

Answer: A. $35.10

Step-by-step explanation:

Since the total money paid for the water for 3months is $95 and there are 31 days in October, 30days in November and 31 days in December totalling 92days. Therefore $95 was charged for water for 92days.

Since the owner sold the house and the rentage stopped 27th November, this shows the person only used water for (31+27) days i.e 58 days in the house.

The amount that will be received by the owner upon closing will be;

Since 92days of water used is equivalent to $95

58days will be equivalent to 58×95/92 = $59.9

The amount received will be

95-59.9 = $35.10 (A)

5 0

4 years ago

200 is blank times ad much as 2

kodGreya [7K]

1oo times 2 i think............

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4 years ago

If f(x)=4-x^2 and g(x)=6x, which expression is equivalent to (g-f)(3)?

dem82 [27]

Sent a picture of the solution.

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4 years ago

The straight line PQ with P(1,6) and Q(-6, 1). PQ is mapped onto P'Q' by a reflection in the line = 2. What are the coordinates

SSSSS [86.1K]

Answer:

$P' = (1,-2)$

Step-by-step explanation:

Given

$P = (1.6)$

$Q = (-6,1)$

Reflection over: $y = 2$

Required

Determine the coordinates of P'

From the given coordinates, the y coordinates of P is 6 and the line of reflection is at y = 2

Since we are to reflect over y = 2, only the y coordinate of P will be affected.

The idea behind reflecting a point over a line is to have an equal distance between [the original point & the line of reflection] and [the new point & the line of reflection]

So, what to do is:

First, calculate the difference between the y coordinates of P and the line of reflection.

The y coordinate of P is 6 and the line of reflection is at y = 2.

So, the difference is: 6 -2 = 4

Next, subtract the calculated difference from the line of reflection to get the y coordinate of P'

y coordinate of P' = 2 - 4 = -2

<em>Hence, the coordinate of P' is: (1,-2)</em>

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3 years ago