Answer:
285.00
Step-by-step explanation:
Because you change 57 to a decimal (57.0) then you multiply.
57.0×2.3=285.00
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Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
Thus to find the perimeter, we add up all the sides to get
sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B
X=27
81 = 3x= 27
So x means 27
H(x) = x - 5
However, it had a domain of all real numbers such that x does not equal 3, since that would cause you to divide by 0.
Answer:
46
Step-by-step explanation:
The geometry can be modeled by a right triangle. The diagonal measure is the hypotenuse, and the height is one leg. The width is the other leg, and can be found using the Pythagorean theorem.
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<h3>Pythagorean theorem</h3>
The relation between the leg lengths (a, b) and the hypotenuse (c) is ...
c² = a² +b²
Solving for b gives ...
b = √(c² -a²)
<h3>application</h3>
In this problem, we have c=55 and a=30. Then the width of the TV is ...
b = √(55² -30²) = √(3025 -900) = √2125
b ≈ 46.098
The width of the TV is about 46.
