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defon
3 years ago
14

One zero of f(x)=x^3-2x^2-5+6 is 1 what are the other zeros of the function

Mathematics
1 answer:
noname [10]3 years ago
8 0

Answer:

the other zeros of this function are {-2, 3}

Step-by-step explanation:

Use synthetic division to find the roots.  The coefficients of this cubic function are 1, -2, -5, 6, and we begin by using 1 as our first divisor:

1    /    1    -2    -5    6

               +1      -1    -6

    --------------------------

         1     -1       -6    0

Because the remainder is zero (0), we can conclude that 1 is indeed a root of the given polynomial.  The quotient is 1x^2  - 1x  - 6, whose roots can be found either through synthetic division or factoring.  In this case the factors are (x - 3) and (x + 2), so the other zeros of this function are {-2, 3}.

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4 0
3 years ago
Read 2 more answers
20 POINTS! Please help
Marysya12 [62]

The complete square will be  (x-3)^{2} = 3

Step-by-step explanation:

Given,

2x^{2} -12x+12=0

or, x^{2} -6x+6=0 [ by eliminating 2 from both the sides]

To make it square

x^{2} -6x+6=0

or, x^{2} -2xX3+9-9+6=0 [ (a+b)^{2}=a^{2} +2ab+b^{2}

or, (x-3)^{2} = 9-6

or, (x-3)^{2} = 3

Hence the correct option is B

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4 years ago
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Hypotenuse leg would be right
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A circle has a cincumarence of 907 16 units,What is the diameter of the circle?
abruzzese [7]

Answer: 288.74

Step-by-step explanation:

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3 years ago
Need help with this problem
Zanzabum

Answer:

C. Priya needs to charge at least $21 per bracelet.

Step-by-step explanation:

117b - 505 \ge 1952

Add 505 to both sides.

117b \ge 2457

Divide both sides by 117.

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