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erik [133]
3 years ago
12

In a newspaper, it was reported that the number of yearly robberies in Springfield in 2013 was 125, and then went down by 12% in

2014. How many robberies were there in Springfield in 2014?
Mathematics
2 answers:
Scorpion4ik [409]3 years ago
7 0
Answer: 110
Solution: 12% of 125= 15
125-15= 110
Hope you get it.
Vladimir79 [104]3 years ago
7 0

Answer:

110

Step-by-step explanation:

  • 2013

No of robberies = 125

Percentage = 100%

  • 2014

No of robberies = 'd'

Percentage = 12% lower than 2013 = 100% - 12%

= 88%

No of robberies in 2014 = 88% of the number of robberies in 2013

'd' = 88/100 × 125

'd' = 0.88 × 125

'd' = 110

2014 robberies = 110 in number

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allochka39001 [22]

Answer:

13. i may be wrong im not sure

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3 years ago
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What is 5 to the power of 3
trapecia [35]
5³ is 5x5x5 so that is 125
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Use the zero product property to find the solutions to the equation 2x2 + x - 1 = 2
Firdavs [7]

Answer:

C

Step-by-step explanation:

Given

2x² + x - 1 = 2 ( subtract 2 from both sides )

2x² + x - 3 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 2 × - 3 = - 6 and sum = + 1

The factors are - 2 and + 3

Use these factors to split the x- term

2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(2x + 3) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - \frac{3}{2}

8 0
3 years ago
A culture started with 4,000 bacteria. After 5 hours, it grew to 4,800 bacteria. Predict how many bacteria will be present after
eimsori [14]
First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646

Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours

Hope it helps!
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3 years ago
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Simplify the expression 4•3+4•x
r-ruslan [8.4K]

Answer:

4x+12

Step-by-step explanation:

4 0
3 years ago
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