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2 years ago

A driver brings a car to a full stop in 2.0s. It’s acceleration is -11 m/s^2. How far did the car travel while braking

Mathematics

2 answers:

tensa zangetsu [6.8K]2 years ago

6 0

Answer:

22 m

Step-by-step explanation:

The distance traveled is ...

d = (1/2)at^2

where "a" is the magnitude of the acceleration.

d = (1/2)(11 m/s^2)(2 s)^2

d = 22 m

The car traveled 22 meters while braking.

Anna11 [10]2 years ago

4 0

Answer: 22

Step-by-step explanation:

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Subtract 15 and 4 , double the difference, and then add two-thirds

mrs_skeptik [129]

15-4 = 11

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3 years ago

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A line passes through $A(1,1)$ and $B(100,1000)$. How many other points with integer coordinates are on the line and strictly be

jonny [76]

Answer:

Step-by-step explanation:

Integers are whole numbers or opposite of whole numbers.

The slope is 1.

How?

Change of y is 100-1=99.

Change of x is 100-1=99.

The slope is 99/99=1 or 1/1.

So if we start at (1,1) and we rise 1 and run 1 right, we get (2,2).

If we do that again from (2,2) we get (3,3).

Following the pattern of going up 1 and right from each new location discovered we get all the of these points:

Start (1,1)

(2,2)

(3,3)

(4,4)

(5,5)

(6,6)

....

(96,96)

(97,97)

(98,98)

(99,99)

end (100,100)

So we just need to count all the numbers from 2 to 99.

99-2+1

97+1

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2 years ago

1 and 1 4th as a decimal

Neporo4naja [7]

1 + 0.25 will equal 1.25

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2 years ago

Write the sum or difference in the standard form a + bi. ( 7 + 5i) - ( -9 + i)

Veseljchak [2.6K]

(7 + 5i) - ( -9 + i)
= 7 + 5i - (-9) - (i)
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3 years ago

Solve the system by using a matrix equation (Picture provided)

Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as $\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]$

A= $\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]$

X= $\left[\begin{array}{c}x\\y\end{array}\right]$

B= $\left[\begin{array}{c}4\\2\end{array}\right]$

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

= (-42)-(-40)

= (-42) + 40 = -2

so, |A| = -2

Adj A= $\left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]$

A⁻¹ = $\left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]$ / -2

A⁻¹ = $\left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]$

X= A⁻¹ B

X= $\left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]$

X= $\left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]$

X= $\left[\begin{array}{c}12-4\\20-7\end{array}\right]$

X= $\left[\begin{array}{c}8\\13\end{array}\right]$

x= 8, y= 13

solution set= (8,13).

Option b is correct.

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3 years ago